sci.math

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Date Sujet#  Auteur
24 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii    +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Moebius
25 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii    i`- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1WM
24 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii    `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how163Jim Burns
25 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii     `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how162WM
26 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii      +- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1FromTheRafters
26 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii      `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how160Jim Burns
26 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii       +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Moebius
26 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii       `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how158WM
26 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how156Jim Burns
26 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how139Tom Bola
2 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how138Jim Burns
2 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how136Tom Bola
2 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how127Jim Burns
2 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii ii+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how124Tom Bola
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iii+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how122Jim Burns
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii+- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Tom Bola
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how120WM
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how4Tom Bola
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how3WM
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Tom Bola
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i  `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how113Jim Burns
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how112WM
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
4 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
5 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how107Jim Burns
5 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how47Ross Finlayson
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how46Jim Burns
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how45Ross Finlayson
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii  +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii  `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how43Ross Finlayson
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii   `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how42Jim Burns
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii    `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how41Ross Finlayson
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii     `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how40Jim Burns
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii      `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how39Ross Finlayson
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii       `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how38Jim Burns
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii        `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how37Ross Finlayson
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii         `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how36Jim Burns
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii          `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how35Ross Finlayson
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii           `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how34Jim Burns
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii            `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how33Ross Finlayson
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             +* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how30Jim Burns
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i`* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how29Ross Finlayson
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how28Jim Burns
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i  `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how27Ross Finlayson
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i   `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how26Jim Burns
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i    `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how25Ross Finlayson
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i     `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how24Ross Finlayson
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      +* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how22Ross Finlayson
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i`* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how21Jim Burns
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how20Ross Finlayson
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i  +* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Ross Finlayson
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i  i`- Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Ross Finlayson
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i  `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how17Jim Burns
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i   `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how16Ross Finlayson
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i    `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how15Ross Finlayson
13 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i     `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how14Jim Burns
13 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i      `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how13Ross Finlayson
13 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i       `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how12Ross Finlayson
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i        `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how11Ross Finlayson
15 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i         `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how10Jim Burns
15 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i          `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how9Ross Finlayson
15 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i           `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how8Jim Burns
16 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i            `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how7Ross Finlayson
16 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i             `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how6Jim Burns
18 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i              `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how5Ross Finlayson
18 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i               `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how4Jim Burns
18 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i                `* Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how3Ross Finlayson
19 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i                 +- Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Ross Finlayson
19 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      i                 `- Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
12 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             i      `- Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii             `* Re: universal quantification, because g?(g?¹(x)) = g(y) [1/2] Re: how2FromTheRafters
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i ii              `- Re: universal quantification, because g?(g?¹(x)) = g(y) [1/2] Re: how1Ross Finlayson
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how59WM
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how56Jim Burns
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how41WM
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how40Jim Burns
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how39WM
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii  `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how38Jim Burns
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how5Moebius
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   i+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how3Moebius
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   ii`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Moebius
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   ii `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1WM
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   i`- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how4Moebius
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   i+- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Moebius
9 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Jim Burns
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   i `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1WM
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii   `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how28WM
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    +* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how13FromTheRafters
13 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i`* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how12WM
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i +* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how5FromTheRafters
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i i`* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how4WM
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i i `* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how3FromTheRafters
15 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i i  `* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how2WM
15 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i i   `- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1Moebius
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i +* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how2Chris M. Thomasson
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i i`- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1WM
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i `* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how4Moebius
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i  +- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1Moebius
15 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i  `* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how2WM
15 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i   `- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1Moebius
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how10Jim Burns
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how7Moebius
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    ii+* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how5Jim Burns
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    iii`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how4Moebius
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    iii +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Moebius
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    iii i`- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    iii `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
13 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    ii`- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1WM
13 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2WM
14 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    i `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii    `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how4Chris M. Thomasson
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii     `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how3Chris M. Thomasson
10 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii      `* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how2FromTheRafters
11 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i ii       `- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i`* Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how14Ross Finlayson
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i +* Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how6Chris M. Thomasson
7 Jun 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i i`* Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how5Chris M. Thomasson
7 Jun 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i i `* Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how4Ross Finlayson
8 Jun 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i i  `* Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how3Chris M. Thomasson
8 Jun 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i i   `* Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Ross Finlayson
8 Jun 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i i    `- Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i `* Re: universal quantifiers, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how7Jim Burns
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i  `* Re: universal quantifiers, because g?(g?¹(x)) = g(y) [1/2] Re: how6FromTheRafters
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i   `* Re: universal quantifiers, because g?(g?¹(x)) = g(y) [1/2] Re: how5Ross Finlayson
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i    `* Re: universal quantifiers, because g?(g?¹(x)) = g(y) [1/2] Re: how4Ross Finlayson
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i     `* Re: universal quantifiers, because g?(g?¹(x)) = g(y) [1/2] Re: how3Ross Finlayson
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i      `* Re: universal quantifiers, because g?(g?¹(x)) = g(y) [1/2] Re: how2FromTheRafters
8 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i i       `- Re: universal quantifiers, because g?(g?¹(x)) = g(y) [1/2] Re: how1Ross Finlayson
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Richard Damon
7 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i i `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Moebius
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii i  `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1WM
4 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Richard Damon
4 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iiii `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Moebius
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii iii`- Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how1WM
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii ii`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2WM
4 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii ii `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i`* Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how8WM
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i +* Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how5Tom Bola
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i i`* Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how4Ross Finlayson
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i i +* Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how2Tom Bola
4 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i i i`- Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how1Ross Finlayson
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i i `- Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how1Jim Burns
4 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i `* Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how2Richard Damon
6 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii i  `- Re: because g⤨(g⁻¹(x))= g(y) [1/2] Re: how1WM
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        ii `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1WM
27 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how16WM
28 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how15Jim Burns
28 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i  +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Ross Finlayson
30 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i  +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Moebius
30 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i  i`- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Moebius
30 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i  `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how11WM
30 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i   +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Moebius
30 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i   +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Moebius
30 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i   +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Tom Bola
1 May 24 ii    i  i     i     ii             i i  i       i   i     ii        i   i`- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Ross Finlayson
30 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        i   +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
1 May 24 ii    i  i     i     ii             i i  i       i   i     ii        i   `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how5Moebius
1 May 24 ii    i  i     i     ii             i i  i       i   i     ii        i    +- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Tom Bola
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        i    `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how3WM
3 May 24 ii    i  i     i     ii             i i  i       i   i     ii        i     `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2joes
4 May 24 ii    i  i     i     ii             i i  i       i   i     ii        i      `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
26 Apr 24 ii    i  i     i     ii             i i  i       i   i     ii        `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Chris M. Thomasson
22 Apr 24 ii    i  i     i     ii             i i  i       i   i     i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how12Moebius
22 Apr 24 ii    i  i     i     ii             i i  i       i   i     i `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how11Jim Burns
22 Apr 24 ii    i  i     i     ii             i i  i       i   i     i  `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how10Moebius
22 Apr 24 ii    i  i     i     ii             i i  i       i   i     i   +* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how3Tom Bola
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     i   i`* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how2Moebius
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     i   i `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Jim Burns
22 Apr 24 ii    i  i     i     ii             i i  i       i   i     i   `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how6Jim Burns
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     i    +- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1FromTheRafters
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     i    `* Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how4Moebius
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     i     `* Re: because g?(g?¹(x)) = g(y) [1/2] Re: how3FromTheRafters
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     i      +- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1Moebius
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     i      `- Re: because g?(g?¹(x)) = g(y) [1/2] Re: how1Jim Burns
23 Apr 24 ii    i  i     i     ii             i i  i       i   i     `- Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how1Richard Damon
19 Apr 24 ii    i  i     i     ii             i i  i       i   `* because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how15Jim Burns
19 Apr 24 ii    i  i     i     ii             i i  i       i    +* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how12WM
19 Apr 24 ii    i  i     i     ii             i i  i       i    i+- Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how1Ross Finlayson
20 Apr 24 ii    i  i     i     ii             i i  i       i    i`* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how10Jim Burns
20 Apr 24 ii    i  i     i     ii             i i  i       i    i `* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how9WM
20 Apr 24 ii    i  i     i     ii             i i  i       i    i  +* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how3Richard Damon
20 Apr 24 ii    i  i     i     ii             i i  i       i    i  i`* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how2WM
20 Apr 24 ii    i  i     i     ii             i i  i       i    i  i `- Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how1Richard Damon
20 Apr 24 ii    i  i     i     ii             i i  i       i    i  +* Re: because g?(g?¹(x)) = g(y) [2/2] Re: how2FromTheRafters
20 Apr 24 ii    i  i     i     ii             i i  i       i    i  i`- Re: because g?(g?¹(x)) = g(y) [2/2] Re: how1WM
21 Apr 24 ii    i  i     i     ii             i i  i       i    i  `* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how3Moebius
22 Apr 24 ii    i  i     i     ii             i i  i       i    i   `* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how2WM
22 Apr 24 ii    i  i     i     ii             i i  i       i    i    `- Re: how can a person be so dumb?1Moebius
19 Apr 24 ii    i  i     i     ii             i i  i       i    `* Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how2Ross Finlayson
20 Apr 24 ii    i  i     i     ii             i i  i       i     `- Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how1Ross Finlayson
15 Apr 24 ii    i  i     i     ii             i i  i       `* Re: how2Tom Bola
16 Apr 24 ii    i  i     i     ii             i i  i        `- Re: how1WM
12 Apr 24 ii    i  i     i     ii             i i  `* Re: how8Richard Damon
12 Apr 24 ii    i  i     i     ii             i i   `* Re: how7WM
12 Apr 24 ii    i  i     i     ii             i i    `* Re: how6Richard Damon
12 Apr 24 ii    i  i     i     ii             i i     `* Re: how5WM
12 Apr 24 ii    i  i     i     ii             i i      +- Re: how1Richard Damon
12 Apr 24 ii    i  i     i     ii             i i      `* Re: how3Chris M. Thomasson
12 Apr 24 ii    i  i     i     ii             i i       `* Re: how2Tom Bola
12 Apr 24 ii    i  i     i     ii             i i        `- Re: how1Chris M. Thomasson
11 Apr 24 ii    i  i     i     ii             i `- Re: how1Chris M. Thomasson
18 Apr 24 ii    i  i     i     ii             `* Re: how19Phil Carmody
18 Apr 24 ii    i  i     i     ii              `* Re: how18WM
18 Apr 24 ii    i  i     i     ii               +- Re: how1Tom Bola
19 Apr 24 ii    i  i     i     ii               `* Re: how16Richard Damon
19 Apr 24 ii    i  i     i     ii                `* Re: how15WM
20 Apr 24 ii    i  i     i     ii                 `* Re: how14Richard Damon
20 Apr 24 ii    i  i     i     ii                  `* Re: how13WM
20 Apr 24 ii    i  i     i     ii                   `* Re: how12Richard Damon
20 Apr 24 ii    i  i     i     ii                    `* Re: how11WM
20 Apr 24 ii    i  i     i     ii                     +* Re: how5Richard Damon
22 Apr 24 ii    i  i     i     ii                     i`* Re: how4WM
22 Apr 24 ii    i  i     i     ii                     i +* Re: how2Moebius
22 Apr 24 ii    i  i     i     ii                     i i`- Re: how1Moebius
23 Apr 24 ii    i  i     i     ii                     i `- Re: how1Richard Damon
21 Apr 24 ii    i  i     i     ii                     `* Re: how5Moebius
22 Apr 24 ii    i  i     i     ii                      `* Re: how4WM
22 Apr 24 ii    i  i     i     ii                       +- Re: how (holy shit!)1Moebius
23 Apr 24 ii    i  i     i     ii                       +- Re: how1Chris M. Thomasson
23 Apr 24 ii    i  i     i     ii                       `- Re: how1Richard Damon
5 Apr 24 ii    i  i     i     i`- Re: Contradiction of bijections as a measure for infinite sets1FromTheRafters
4 Apr 24 ii    i  i     i     `* Re: Contradiction of bijections as a measure for infinite sets32Jim Burns
4 Apr 24 ii    i  i     i      `* Re: Contradiction of bijections as a measure for infinite sets31WM
4 Apr 24 ii    i  i     i       `* Re: Contradiction of bijections as a measure for infinite sets30Jim Burns
5 Apr 24 ii    i  i     i        `* Re: Contradiction of bijections as a measure for infinite sets29WM
5 Apr 24 ii    i  i     i         `* Re: Contradiction of bijections as a measure for infinite sets28Jim Burns
6 Apr 24 ii    i  i     i          `* Re: Contradiction of bijections as a measure for infinite sets27WM
6 Apr 24 ii    i  i     i           `* Re: Contradiction of bijections as a measure for infinite sets26Jim Burns
6 Apr 24 ii    i  i     i            `* Re: Contradiction of bijections as a measure for infinite sets25WM
7 Apr 24 ii    i  i     i             `* Re: Contradiction of bijections as a measure for infinite sets24Jim Burns
8 Apr 24 ii    i  i     i              `* Re: Contradiction of bijections as a measure for infinite sets23WM
9 Apr 24 ii    i  i     i               `* Re: Contradiction of bijections as a measure for infinite sets22Jim Burns
9 Apr 24 ii    i  i     i                +* Re: Contradiction of bijections as a measure for infinite sets2Moebius
10 Apr 24 ii    i  i     i                i`- Re: Contradiction of bijections as a measure for infinite sets1Jim Burns
9 Apr 24 ii    i  i     i                `* Re: Contradiction of bijections as a measure for infinite sets19WM
9 Apr 24 ii    i  i     i                 +* Re: Contradiction of bijections as a measure for infinite sets5Tom Bola
9 Apr 24 ii    i  i     i                 i+* Re: Contradiction of bijections as a measure for infinite sets3Moebius
9 Apr 24 ii    i  i     i                 ii`* Re: Contradiction of bijections as a measure for infinite sets2Tom Bola
9 Apr 24 ii    i  i     i                 ii `- Re: Contradiction of bijections as a measure for infinite sets1Moebius
10 Apr 24 ii    i  i     i                 i`- Re: Contradiction of bijections as a measure for infinite sets1Chris M. Thomasson
9 Apr 24 ii    i  i     i                 +- Re: Contradiction of bijections as a measure for infinite sets1Moebius
9 Apr 24 ii    i  i     i                 +* Re: Contradiction of bijections as a measure for infinite sets5Jim Burns
10 Apr 24 ii    i  i     i                 i`* Re: Contradiction of bijections as a measure for infinite sets4WM
10 Apr 24 ii    i  i     i                 i `* Re: Contradiction of bijections as a measure for infinite sets3Jim Burns
11 Apr 24 ii    i  i     i                 i  `* Re: Contradiction of bijections as a measure for infinite sets2Ross Finlayson
11 Apr 24 ii    i  i     i                 i   `- Re: Contradiction of bijections as a measure for infinite sets1Jim Burns
10 Apr 24 ii    i  i     i                 +* Re: Contradiction of bijections as a measure for infinite sets4Richard Damon

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