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On 6/8/2025 10:42 PM, dbush wrote:And HHH fails to see the specification of the x86 instructions. It aborts before it can see how the program ends.On 6/8/2025 11:39 PM, olcott wrote:There you go.On 6/8/2025 10:32 PM, dbush wrote:>On 6/8/2025 11:16 PM, olcott wrote:>On 6/8/2025 10:08 PM, dbush wrote:>On 6/8/2025 10:50 PM, olcott wrote:>void DDD()>
{
HHH(DDD);
return;
}
>
The *input* to simulating termination analyzer HHH(DDD)
No it's not, as halt deciders / termination analyzers work with algorithms,
That is stupidly counter-factual.
>
That you think that shows that
My understanding is deeper than yours.
No decider ever takes any algorithm as its input.
But they take a description/specification of an algorithm,
which is what is meant in this context.It turns out that this detail makes a big difference.
And because your HHH does not work with the description/specification of an algorithm, by your own admission, you're not working on the halting problem.HHH(DDD) takes a finite string of x86 instructions
>
that specify that HHH simulates itself simulating DDD.
There are more steps, I don't want to overwhelm you.Yes. For some incorrect reason the programmer of HHH assumes that the simulation of HHH does not halt, when he knows that HHH does halt.
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