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Am Fri, 20 Jun 2025 09:53:41 -0500 schrieb olcott:That is counter-factual and it you knew c wellOn 6/20/2025 4:42 AM, Fred. Zwarts wrote:Op 19.jun.2025 om 17:23 schreef olcott:On 6/19/2025 3:55 AM, Fred. Zwarts wrote:Op 18.jun.2025 om 17:41 schreef olcott:On 6/18/2025 4:36 AM, Fred. Zwarts wrote:Op 17.jun.2025 om 16:36 schreef olcott:It was an agreement.Indeed, HHH fails to reach the end of the simulation, even thoughThat is counter-factual and over-your-head.
the end is only one cycle further from the point where it gave up
the simulation.
>
Lol, that was the same paragraph.Yes this is factual.>No evidence presented for this claim. Dreaming again?>
Even a beginner understands that when HHH has code to abort and halt,
the simulated HHH runs one cycle behind the simulating HHH, so that
when the simulating HHH aborts, the simulated HHH is only one cycle
away from the same point.
Proving that you do not understand what unreachable code is.
Even a beginner understands that when HHH has code to abort and halt,
the simulated HHH runs one cycle behind the simulating HHH, so that
when the simulating HHH aborts, the simulated HHH is only one cycle
away from the same point.
Every simulated HHH remains one cycle behind its simulator no matter howYes, no simulator can proceed past a call to itself.
deep the recursive simulations go. This means that the outermost
directly executed HHH reaches its abort criteria first.
This means that none of simulated HHH have reached their abort criteria.
This means that their own abort code is unreachable at the point where
the outermost HHH would abort.
Or rather, it hasn't been reached yet.void Infinite_Loop()
It is already unreachable *for HHH*--
when it starts simulating. It is not unreachable when DDD is run directly,
or simulated by anything else that simulates the one cycle more until
the next inner HHH aborts, so clearly HHH is faulty.
This.The failure to reach that point of the simulation is a property of the
simulator, not of the program specified in the input.
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