Sujet : Re: HHH(DDD) is correct to reject its input as non-halting --- EVIDENCE THAT I AM CORRECT
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 22. Jun 2025, 15:51:02
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <103958m$j159$4@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
User-Agent : Mozilla Thunderbird
On 6/22/2025 4:25 AM, Mikko wrote:
void Infinite_Recursion()
{
Infinite_Recursion();
return;
}
void Infinite_Loop()
{
HERE: goto HERE;
return;
}
void DDD()
{
HHH(DDD);
return;
}
int Sipser_D()
{
if (HHH(Sipser_D) == 1)
return 0;
return 1;
}
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
My claim is that each of the above functions correctly
simulated by any termination analyzer HHH that can possibly
exist will never stop running unless aborted by HHH.
Can you affirm or correctly refute this?
Anyway, it was you who changed the topic and then falsely
accused someone else.
In other words you find my latest words irrefutable
so you dodge addressing them.
-- Copyright 2025 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer