Liste des Groupes | Revenir à theory |
On 6/27/2025 2:59 AM, Fred. Zwarts wrote:Another invalid claim without evidence.Op 27.jun.2025 om 06:26 schreef olcott:*It has been doing this correctly for several years*On 6/26/2025 3:46 AM, Fred. Zwarts wrote:>Op 25.jun.2025 om 17:42 schreef olcott:>On 6/25/2025 2:38 AM, Mikko wrote:>On 2025-06-24 14:39:52 +0000, olcott said:>
>*ChatGPT and I agree that*>
The directly executed DDD() is merely the first step of
otherwise infinitely recursive emulation that is terminated
at its second step.
No matter who agrees, the directly executed DDD is mote than
merely the first step of otherwise infinitely recursive
emulation that is terminated at its second step. Not much
more but anyway. After the return of HHH(DDD) there is the
return from DDD which is the last thing DDD does before its
termination.
>
*HHH(DDD) the input to HHH specifies non-terminating behavior*
The fact that DDD() itself halts does not contradict that
because the directly executing DDD() cannot possibly be an
input to HHH in the Turing machine model of computation,
thus is outside of the domain of HHH.
>
Why repeating claims that have been proven incorrect.
The input to HHH is a pointer to code, that includes the code of HHH, including the code to abort and halt. Therefore, it specifies a halting program.
*No, you are using an incorrect measure*
*I have addressed this too many times*
... with invalid measures.
The measure is not whether the simulator can do its job, the measure is what the input specifies.
>>>
DDD correctly simulated by HHH cannot possibly
reach its own simulated "return" statement
final halt state *No matter what HHH does*
Therefore the input to HHH(DD) unequivocally
specifies non-halting behavior.
>
If the simulator cannot analyse this specification,
Les messages affichés proviennent d'usenet.