Sujet : Re: ChatGPT refutes the key rebuttal of my work
De : noreply (at) *nospam* example.org (joes)
Groupes : comp.theoryDate : 16. Oct 2024, 15:01:38
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <4b093cf3a6d52cfe4e763a81d623eb66c817cb7f@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Wed, 16 Oct 2024 08:31:43 -0500 schrieb olcott:
On 10/16/2024 1:33 AM, joes wrote:
Am Tue, 15 Oct 2024 16:51:15 -0500 schrieb olcott:
On 10/15/2024 4:24 PM, joes wrote:
Am Tue, 15 Oct 2024 15:01:36 -0500 schrieb olcott:
On 10/15/2024 2:33 PM, joes wrote:
Am Tue, 15 Oct 2024 13:25:36 -0500 schrieb olcott:
On 10/15/2024 10:17 AM, joes wrote:
Am Tue, 15 Oct 2024 08:11:30 -0500 schrieb olcott:
On 10/15/2024 6:35 AM, Richard Damon wrote:
On 10/14/24 10:13 PM, olcott wrote:
On 10/14/2024 6:50 PM, Richard Damon wrote:
On 10/14/24 11:18 AM, olcott wrote:
On 10/14/2024 7:06 AM, joes wrote:
Am Mon, 14 Oct 2024 04:49:22 -0500 schrieb olcott:
On 10/14/2024 4:04 AM, Mikko wrote:
On 2024-10-13 12:53:12 +0000, olcott said:
>
https://chatgpt.com/share/6709e046-4794-8011-98b7-27066fb49f3e
When you click on the link and try to explain how HHH must be
wrong when it reports that DDD does not terminate because DDD
does terminate it will explain your mistake to you.
I did that, and it admitted that DDD halts, it just tries to
justify why a wrong answer must be right.
It explains in great detail that another different DDD (same
machine code different process context) seems to terminate only
because the recursive emulation that it specifies has been
aborted at its second recursive call.
Yes! It really has different code, by way of the static Root
variable.
No wonder it behaves differently.
There are no static root variables. There never has been any "not
a pure function of its inputs" aspect to emulation.
Oh, did you take out the check if HHH is the root simulator?
There is some code that was obsolete several years ago.
I don't follow your repo. Can you point me to the relevant commit?
It doesn't seem to have happened this year.
https://github.com/plolcott/x86utm Halt7.c was updated last month.
Nope, still there: https://github.com/plolcott/x86utm/blob/master/
Halt7.c#L502
https://github.com/plolcott/x86utm/blob/master/Halt7.c#L502 shows: u32
H(ptr P, ptr I) // 2024-09-15 was HH and edit on line 643
The repository indicates that it was updated: "last month"
Line 502 (if(Root)) wasn't changed.
Every termination analyzer that emulates itself emulating its
input has always been a pure function of this input up to the
point where emulation stops.
That point can never come in the complete simulation of a non-
terminating input, because it is infinite.
You and Richard never seemed to understand this previously.
You seemed to not understand that a simulation may be nonterminating.
Sure yet only when the input is non-terminating.
Sure.
Therefore if HHH even guesses that its input is non-termination then HHH
is correct.
You err because you fail to understand how the same C/x86
function invoked in a different process context can have
different behavior.
Do explain how a pure function can change.
Non-terminating C functions do not ever return, thus cannot
possibly be pure functions.
By "pure" I mean having no side effects. You mean total vs.
partial.
You may be half right. Only the analyzer must be pure.
The input is free to get stuck in an infinite loop.
Sure. How can a function without side effects have different
behaviour?
DDD is free to be totally screwed up every which way.
It is only HHH that must be a pure function.
In which way is DDD screwed up that it is both free of side effects and
referentially intransparent?
In other words you don't have a clue that an input to a termination
analyzer can be non-terminating thus violating the (1) criteria of pure
functions shown below.
I am talking about the referential transparency, not whether the function
is total or partial.
https://en.wikipedia.org/wiki/Total_functional_programming(1) *the function return values are identical for identical arguments*
(no variation with local static variables, non-local variables, mutable
reference arguments or input streams, i.e., referential transparency),
and (2) the function has no side effects (no mutation of local static
variables, non-local variables, mutable reference arguments or input/
output streams).
Yes, this has nothing to do with termination. Your function
Decide_Halting_HH(..., u32 Root) (line 473) is not pure though.
When-so-ever any input to a termination analyzer is
non-terminating for any reason then this input is not a pure function.
s/pure/total
Terminating C functions must reach their "return" statement.
Which DDD does.
HHH is a pure function of its input the whole time that it is
emulating.
DDD has no inputs and is allowed to be any finite string of x86
code.
Inputs to HHH are by no means required to ever return AT ALL.
I thought DDD was fixed to only call HHH(DDD)?
Inputs are not required to be pure functions.
Weren't we discussing the halting DDD(){HHH(DDD);} before?
For many months now I have been talking about the termination analyzer
HHH applied to input DDD.
I am not aware of ever referring to HHH as a halt decider. When I talk
about halt deciders I talk about the Linz proof.
I am, as of a couple months back. This is still related to the Linz
proof.
-- Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:It is not guaranteed that n+1 exists for every n.