Sujet : Re: Any honest person that knows the x86 language can see... predict correctly
De : noreply (at) *nospam* example.org (joes)
Groupes : comp.theoryDate : 01. Aug 2024, 16:44:02
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <754c182e15a6e06e7133446c48f85c041088f0f4@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Thu, 01 Aug 2024 08:04:23 -0500 schrieb olcott:
On 8/1/2024 7:56 AM, Fred. Zwarts wrote:
Op 01.aug.2024 om 13:51 schreef olcott:
On 8/1/2024 2:46 AM, Fred. Zwarts wrote:
Op 01.aug.2024 om 05:51 schreef olcott:
On 7/31/2024 10:08 PM, wij wrote:
On Tue, 2024-07-30 at 18:50 -0500, olcott wrote:
>
It is not supposed to be a general solution to the halting
problem.
it only shows how the "impossible" input is correctly determined
to be non halting.
But how do you determine it is non-halting?
As I know you are even unable to define what 'halt' mean !!!
If DDD correctly emulated by HHH cannot possibly reach its return
instruction then it never halts.
>
But a correct simulation is impossible.
When HHH does what-ever-the-hell the x86 semantics specifies then HHH
is correct.
But since HHH deviates from the semantics of the x86 language (by
skipping instructions of a halting program) it is incorrect.
Only a freaking moron would believe that a non terminating input should
be simulated forever.
I mean, how many iterations of an infinite loop can I skip simulating or
how many do I have to simulate to get identical behaviour?
-- Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:It is not guaranteed that n+1 exists for every n.