Sujet : Re: Who knows that DDD correctly simulated by HHH cannot possibly reach its own return instruction final state?
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : comp.theoryDate : 06. Aug 2024, 02:32:13
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <ad3a7354ca32b7b9adb23db743347f3f12aaec63@i2pn2.org>
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User-Agent : Mozilla Thunderbird
On 8/5/24 8:07 PM, olcott wrote:
On 8/5/2024 5:59 PM, Richard Damon wrote:
On 8/5/24 9:49 AM, olcott wrote:
On 8/5/2024 2:39 AM, Mikko wrote:
On 2024-08-04 18:59:03 +0000, olcott said:
>
On 8/4/2024 1:51 PM, Richard Damon wrote:
On 8/4/24 9:53 AM, olcott wrote:
On 8/4/2024 1:22 AM, Fred. Zwarts wrote:
Op 03.aug.2024 om 18:35 schreef olcott:
>>>> ∞ instructions of DDD correctly emulated by HHH[∞] never
reach their own "return" instruction final state.
>
So you are saying that the infinite one does?
>
>
Dreaming again of HHH that does not abort? Dreams are no substitute for facts.
The HHH that aborts and halts, halts. A tautology.
>
void DDD()
{
HHH(DDD);
return;
}
>
That is the right answer to the wrong question.
I am asking whether or not DDD emulated by HHH
reaches its "return" instruction.
>
But the "DDD emulated by HHH" is the program DDD above,
>
When I say DDD emulated by HHH I mean at any level of
emulation and not and direct execution.
>
If you mean anything other than what the words mean you wihout
a definition in the beginning of the same message then it is
not reasonable to expect anyone to understand what you mean.
Instead people may think that you mean what you say or that
you don't know what you are saying.
>
>
If you don't understand what the word "emulate" means look it up.
>
DDD (above) cannot possibly reach its own "return" instruction halt
state when its machine code is correctly emulated by HHH.
>
>
Only because an HHH that does so never returns to anybody.
>
Do you really not understand that recursive emulation <is>
isomorphic to infinite recursion?
Not when the emulation is conditional.
void Infinite_Recursion()
{
Infinite_Recursion();
return;
}
Does infinite recursion ever reach its own "return"
instruction halt state?
Nope, but DDD() does, as the correct x86 emulation of it shows (not the incorrect, and partial emulation done by the HHH that it calls)
Sorry, you are just caught in your own lies. You need HHH to be two different programs at the same time, when it can't be.
YOu are just proving you don't understand even the basics of the topics you are trying to talk about, but have just made yourself into a pathetic, ignorant, pathological lying idiot that reckless disregards the truth because you beleive the lies you brainwashed yourself so much you just can't look at the truth,