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On 8/19/2024 8:24 PM, Richard Damon wrote:No, it is just a basic fact that NO emulator can properly emulate the about input past the 4th instruction, as the data just isn't provided.On 8/19/24 8:50 PM, olcott wrote:void DDD()
{
HHH(DDD);
return;
}
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
*It is a basic fact that DDD emulated by HHH according to*
*the semantics of the x86 language cannot possibly stop*
*running unless aborted* (out of memory error excluded)
X = DDD emulated by HHH∞ according to the semantics of the x86 languageNope, and HHHn creates a DDDn that will call HHHn that will return to it after emulating n steps, and then DDDn will halt
Y = HHH∞ never aborts its emulation of DDD
Z = DDD never stops running
The above claim boils down to this: (X ∧ Y) ↔ Z
void EEE()
{
HERE: goto HERE;
}
HHHn correctly predicts the behavior of DDD the same
way that HHHn correctly predicts the behavior of EEE.
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