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On 3/4/2025 3:14 AM, Fred. Zwarts wrote:No, and the fact you claim that is just proof you don't understand what you are talking about.Op 04.mrt.2025 om 04:07 schreef olcott:The only valid rebuttal is to show all of the steps ofint DD()I wonder why Olcott keeps repeating that HHH fails to reach the 'ret' instruction, where the direct execution or world-class simulators have no problem to reach the 'ret' instruction of exactly the same finite string as input.
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
>
_DD()
[00002133] 55 push ebp ; housekeeping
[00002134] 8bec mov ebp,esp ; housekeeping
[00002136] 51 push ecx ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04
[00002144] 8945fc mov [ebp-04],eax
[00002147] 837dfc00 cmp dword [ebp-04],+00
[0000214b] 7402 jz 0000214f
[0000214d] ebfe jmp 0000214d
[0000214f] 8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp
[00002154] 5d pop ebp
[00002155] c3 ret
Size in bytes:(0035) [00002155]
>
DD correctly emulated by HHH cannot possibly
reach its own "ret" instruction and terminate normally.
exactly how DD correctly emulated by HHH reaches its
own "ret" instruction.
Is he proud of this failure of his HHH?
Why doesn't he change his HHH, e.g. by simulating the call to HHH with a replacement with the return value of HHH, so that he can reach the 'ret' instruction? It is such a simple modification and it will fix at least the problem that the simulation does not reach the 'ret' instruction.
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