Re: Can D simulated by H terminate normally?

On 5/2/24 2:46 PM, olcott wrote:

On 5/2/2024 6:03 AM, Richard Damon wrote:

On 5/2/24 12:21 AM, olcott wrote:

On 5/1/2024 7:28 PM, Richard Damon wrote:

On 5/1/24 11:51 AM, olcott wrote:

Every D simulated by H that cannot possibly stop running unless
aborted by H does specify non-terminating behavior to H. When
H aborts this simulation that does not count as D halting.

>
Which is just meaningless gobbledygook by your definitions.
>
It means that
>
int H(ptr m, ptr d) {
    return 0;
}
>

>
Your H is not simulating D at all thus not
"Every D simulated by H" quoted above

>
Yes it is, it is just aborting the simulation before it started.
>

 D is never simulated by H is not the same as D is simulated by H.
D is simulated by H entails that 1 to N steps are simulated and
then the simulation is aborted or the simulation is never aborted.
 

Then simulate EXACTLY 1 step and abort.
It makes all but the most trivial programs "non-halting."
Again, a TOY.,