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On 6/4/24 10:55 PM, olcott wrote:In other words you have always known that I am correctOn 6/4/2024 9:45 PM, Richard Damon wrote:No, it specifies that it HALTS, since HH(DD,DD) will return 0.On 6/4/24 10:28 PM, olcott wrote:>On 6/4/2024 9:22 PM, Richard Damon wrote:>On 6/4/24 9:54 PM, olcott wrote:>On 6/4/2024 8:48 PM, Richard Damon wrote:>On 6/4/24 5:53 PM, olcott wrote:>https://liarparadox.org/DD_correctly_simulated_by_HH_is_Proven.pdf>
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At least 100 people kept denying the easily verified fact that the above
link conclusively proves that DD <is> correctly simulated by HH.
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It has been just like I smash a Boston cream pie in their face and they
persistently deny that there ever was any pie as this pie drips from
their face.
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The problem iks you use the WRONG DEFINITION of "Simulated Correctly" to allow the simulation to say anything about the behavior of the machine being simulated.
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*I conclusively proved otherwise in the above link*
You CAN'T provd that a definition is wrong.
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*Try and provide a counter-example or implicitly admit that you cannot*
*Try and provide a counter-example or implicitly admit that you cannot*
*Try and provide a counter-example or implicitly admit that you cannot*
What are you asking for a counter example of?
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The machine description of DD specifies that it does not halt to
simulating halt decider HH and you already know that you cannot
possibly prove otherwise.
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