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On 7/1/2024 1:05 AM, Mikko wrote:The x86 semantics say that an aborted simulation returns.On 2024-06-30 17:18:09 +0000, olcott said:>
Richard just said that he affirms that when DDD correctly simulated by
HHH calls HHH(DDD) that this call returns even though the semantics of
the x86 language disagrees.
You are inconsistent about whether HHH returns or not.It is your HHH so you should know whether it returns. Others may haveI have never lied about this.
wrong impression about it if they have trusted your lies.
DDD is emulated by HHH which calls an emulated HHH(DDD) toDDD running by itself does not stop. HHH stops simulating it.
repeat the process until aborted. Once aborted the DDD emulated by HHH
immediately stops.
At no point in this emulation does the call from DDD emulatedWhere does the outer call to HHH get stuck after aborting?
by HHH to HHH(DDD) ever return.
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