Re: Who here understands that the last paragraph is Necessarily true?

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Sujet : Re: Who here understands that the last paragraph is Necessarily true?
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory
Date : 15. Jul 2024, 14:26:22
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v7381u$mjis$13@dont-email.me>
References : 1 2 3 4
User-Agent : Mozilla Thunderbird
On 7/15/2024 3:23 AM, Mikko wrote:
On 2024-07-14 14:38:31 +0000, olcott said:
 
On 7/14/2024 3:09 AM, Mikko wrote:
On 2024-07-13 20:15:56 +0000, olcott said:
>
typedef void (*ptr)();
int HHH(ptr P);
>
void Infinite_Loop()
{
   HERE: goto HERE;
}
>
void Infinite_Recursion()
{
   Infinite_Recursion();
}
>
void DDD()
{
   HHH(DDD);
}
>
int main()
{
   HHH(Infinite_Loop);
   HHH(Infinite_Recursion);
   HHH(DDD);
}
>
Any input that must be aborted to prevent the non
termination of HHH necessarily specifies non-halting
behavior or it would never need to be aborted.
>
Everyone understands that DDD specifies a halting behaviour if HHH(DDD) does,
>
>
*You can comprehend this is a truism or fail to*
*comprehend it disagreement is necessarily incorrect*
Any input that must be aborted to prevent the non
termination of HHH necessarily specifies non-halting
behavior or it would never need to be aborted.
>
Disagreeing with the above is analogous to disagreeing
with arithmetic.
 That the input is aborted does not mean that the input must be aborted.
Weasel words. This is an axiom:
Input XXX must be aborted to prevent the non-termination of HHH.
 From the fact that XXX must be aborted we can conclude that XXX must be aborted.
I can't see how you were simply not flat out dishonest.

And if the input specifies that its input is aborted then the behaviour
is not non-terminating.
 
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

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