Sujet : Re: Hypothetical possibilities -- I reread this again more carefully
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 22. Jul 2024, 13:47:33
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v7lkd5$laot$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
User-Agent : Mozilla Thunderbird
On 7/22/2024 6:27 AM, Richard Damon wrote:
On 7/22/24 12:49 AM, olcott wrote:
On 7/21/2024 6:37 AM, Richard Damon wrote:
On 7/21/24 12:15 AM, olcott wrote:
On 7/20/2024 10:51 PM, Richard Damon wrote:
>
No, the SIMULA*TION* stops running, the SIMULATED (which is the actual program) behaviof continues.
>
>
Yes you are clueless.
>
void DDD()
{
HHH(DDD);
return;
}
>
When the simulation stops running the whole program
exits to the operating system.
>
>
Which just shows you don't understand the MEANING of the behavior of a program.
>
Behvior is the UNCHANING attribute of what the program does when it is run. As such, aborting a simulation of it doesn't stop behavior.
>
>
*You are still totally clueless*
>
As soon as HHH(DDD) aborts its simulation HHH immediately
exits to the operating system.
>
No it return to its caller, or it isn't a decider.
void DDD()
{
HHH(DDD);
return;
}
int main()
{
HHH(DDD);
}
Unlike you I can admit my mistake.
As soon as HHH(DDD) aborts its simulation HHH immediately
returns to main() and
exits to the operating system.
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer
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