Sujet : Re: This function proves that only the outermost HHH examines the execution trace
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 27. Jul 2024, 15:48:21
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v82tr5$3dftr$2@dont-email.me>
References : 1 2
User-Agent : Mozilla Thunderbird
On 7/27/2024 3:36 AM, Fred. Zwarts wrote:
Op 26.jul.2024 om 17:56 schreef olcott:
This is meant for Mike, Joes and Fred don't have the technical competence to understand it.
I have pity with you,
I am not the one that stupidly believes that a non-terminating
input must be emulated to non-existent completion or the emulation
is wrong.
That the first HHH to see the non-halting behavior pattern must
abort or none of them abort is simply too difficult for you.
that you need such lame excuses to hide that you do not understand where you are talking about.
But I see you can't help to react like this. If you would really understand the errors you make, you would realise how embarrassing it is for you. So, I understand that you try to hide it.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer