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On 8/3/2024 3:06 AM, Mikko wrote:When it cannot possibly reach its own return instruction, it is an incorrect simulation, no matter how often you repeat the word 'correct'.On 2024-08-02 02:09:38 +0000, olcott said:[Who here is too stupid to know that DDD correctly simulated
>*This algorithm is used by all the simulating termination analyzers*>
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
If simulating halt decider H correctly simulates its input D
until H correctly determines that its simulated D would never
stop running unless aborted then
>
H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>
DDD is correctly emulated by HHH according to the x86
language semantics of DDD and HHH including when DDD
emulates itself emulating DDD
>
*UNTIL*
>
HHH correctly determines that never aborting this
emulation would cause DDD and HHH to endlessly repeat.
The determination is not correct. DDD is a halting computation, as
correctely determined by HHH1 or simly calling it from main. It is
not possible to correctly determine that ha haling computation is
non-halting, as is self-evdent from the meaning of the words.
>
by HHH cannot possibly reach its own return instruction?]
void DDD()
{
HHH(DDD);
return;
}
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