Re: Who here is too stupid to know that DDD correctly simulated by HHH cannot possibly reach its own return instruction?

Op 04.aug.2024 om 15:11 schreef olcott:

On 8/4/2024 1:26 AM, Fred. Zwarts wrote:

Op 03.aug.2024 om 17:20 schreef olcott:>>

When you try to show how DDD simulated by HHH does
reach its "return" instruction you must necessarily
must fail unless you cheat by disagreeing with the
semantics of C. That you fail to have a sufficient
understanding of the semantics of C is less than no
rebuttal what-so-ever.

>
Fortunately that is not what I try, because I understand that HHH cannot possibly simulate itself correctly.
>

 void DDD()
{
   HHH(DDD);
   return;
}
 In other words when HHH simulates itself simulating DDD it
is supposed to do something other than simulating itself
simulating DDD ???  Do you expect it to make a cup of coffee?
 

Is English too difficult for you. I said HHH cannot do it correctly. HHH is supposed to do it correctly, but it cannot do it correctly.
Are you caught in thinking that it can do it correctly? It cannot do it correctly. So, assuming it does it correctly is incorrect.
Stop talking about what else it should do, it cannot do it correctly.