Sujet : Re: HHH maps its input to the behavior specified by it --- reaches its halt state --- Which DDD does if HHH(DDD) returns and answer, which it does since it is a decider.
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 10. Aug 2024, 02:52:19
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v96h4j$d1aa$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
User-Agent : Mozilla Thunderbird
On 8/9/2024 8:46 PM, Richard Damon wrote:
On 8/9/24 9:25 PM, olcott wrote:
On 8/9/2024 8:05 PM, Richard Damon wrote:
On 8/9/24 8:52 PM, olcott wrote:
>
When we look at every HHH that can possibly exist then
we see that DDD correctly emulated by each one of these
cannot possibly reach its "return" instruction halt state.
>
But ONLY ONE of those actuallu "correctly emulates" the input, and that one isn't a decider.
>
>
In other words you are trying to keep getting away
with the bald-faced lie that when HHH correctly
emulates N instructions of DDD (where N > 0) that
it did not correctly emulate any instructions of DDD.
>
*Give it up you lost you are stuck in repeat mode*
*Give it up you lost you are stuck in repeat mode*
*Give it up you lost you are stuck in repeat mode*
>
So, I guess you don't understand English.
Where did I say that simulating N instructions correctly is not simulating ANY instructions correctly.
*Shown above*
"But ONLY ONE of those actuallu "correctly emulates" the input..."
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
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