Sujet : Re: key error in all the proofs --- Correction of Fred
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 16. Aug 2024, 15:42:13
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v9nog5$1fe76$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
User-Agent : Mozilla Thunderbird
On 8/16/2024 9:28 AM, Richard Damon wrote:
On 8/16/24 10:09 AM, olcott wrote:
On 8/16/2024 8:34 AM, Mikko wrote:
On 2024-08-16 12:02:00 +0000, olcott said:
>
>
I must go one step at a time.
>
That's reasonable in a discussion. The one thing you were discussing
above is what is the meaning of the output of HHH. Its OK to stay
at that step until we are sure it is understood.
>
>
void DDD()
{
HHH(DDD);
return;
}
>
Unless an unlimited emulation of DDD by HHH
can reach the "return" instruction of DDD it is
construed that this instance of DDD never halts.
But that also construes that HHH is a program that DOES an unlimited emulation of DDD, and thus isn't a decider
Not at all. never has.
HHH must predict what the behavior of an unlimited
simulation would be.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
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