Re: ChatGPT refutes the key rebuttal of my work

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Sujet : Re: ChatGPT refutes the key rebuttal of my work
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory
Date : 16. Oct 2024, 18:46:01
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <veou4p$2baph$3@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
User-Agent : Mozilla Thunderbird
On 10/16/2024 12:27 PM, joes wrote:
Am Wed, 16 Oct 2024 10:39:21 -0500 schrieb olcott:
On 10/16/2024 9:45 AM, joes wrote:
Am Wed, 16 Oct 2024 09:11:22 -0500 schrieb olcott:
On 10/16/2024 9:01 AM, joes wrote:
Am Wed, 16 Oct 2024 08:31:43 -0500 schrieb olcott:
On 10/16/2024 1:33 AM, joes wrote:
Am Tue, 15 Oct 2024 16:51:15 -0500 schrieb olcott:
On 10/15/2024 4:24 PM, joes wrote:
 
Terminating C functions must reach their "return" statement.
Which DDD does.
THIS IS ALSO THE INDUSTRY STANDARD DEFINITION It is stipulated that
*correct_x86_emulation* means that a finite string of x86 instructions
is emulated according to the semantics of the x86 language beginning
with the first bytes of this string.
You are not simulating the given program, but a version that differs in
the abort check.
HHH is correctly emulating (not simulating) the x86 language finite
string of DDD including emulating the finite string of itself emulating
the finite string of DDD up until the point where the emulated emulated
DDD would call HHH(DDD) again.

Whereupon the simulated HHH would abort, if it weren't unnecessarily
aborted.
 
If the first HHH to meet its abort criteria does not
act on this criteria then none of them do.

When HHH is an x86 emulation based termination analyzer then each DDD
*correctly_emulated_by* any HHH that it calls never returns.
It is not a correct emulation if it has a different termination status.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

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