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On 11/3/2024 6:11 AM, Mikko wrote:It does not add any clarity to the last paragraph beforeOn 2024-11-02 12:46:47 +0000, olcott said:That is why I used to fully defined semantics of the x86
On 11/2/2024 5:49 AM, Mikko wrote:So even you can make the ridiculous mistake to regard the currentlyOn 2024-11-01 12:26:58 +0000, olcott said:This is simple enough that people cannot be confused.
On 11/1/2024 5:58 AM, Mikko wrote:On 2024-10-31 12:50:00 +0000, olcott said:Inconsistent with the currently received view is
On 10/31/2024 5:49 AM, Mikko wrote:Probably but not to anything quoted above.On 2024-10-29 14:35:34 +0000, olcott said:100% perfectly relevant within the philosophy of computation
On 10/29/2024 2:57 AM, Mikko wrote:- irrelevantOn 2024-10-29 00:57:30 +0000, olcott said:*That people fail to agree with this and also fail to*
On 10/28/2024 6:56 PM, Richard Damon wrote:That statement does not fully reject simulation but is correct inOn 10/28/24 11:04 AM, olcott wrote:Ultimately I trust Linz the most on this:On 10/28/2024 6:16 AM, Richard Damon wrote:Nope, read the problem you have quoted in the past.The machine being used to compute the Halting Function has taken a finite string description, the Halting Function itself always took a Turing Machine,That is incorrect. It has always been the finite string Turing Machine
description of a Turing machine is the input to the halt decider.
There are always been a distinction between the abstraction and the
encoding.
the problem is: given the description of a Turing machine
M and an input w, does M, when started in the initial
configuration qow, perform a computation that eventually halts?
https://www.liarparadox.org/Peter_Linz_HP_317-320.pdf
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
Linz also makes sure to ignore that the behavior of ⟨Ĥ⟩ ⟨Ĥ⟩
correctly simulated by embedded_H cannot possibly reach
either ⟨Ĥ.qy⟩ or ⟨Ĥ.qn⟩ because like everyone else he rejects
simulation out of hand:
We cannot find the answer by simulating the action of M on w,
say by performing it on a universal Turing machine, because
there is no limit on the length of the computation.
the observation that non-halting cannot be determied in finite time
by a complete simulation so someting else is needed instead of or
in addition to a partial simulation. Linz does include simulationg
Turing machines in his proof that no Turing machine is a halt decider.
*correctly point out any error seems to indicate dishonestly*
*or lack of technical competence*
DDD emulated by HHH according to the semantics of the x86
language cannot possibly reach its own "return" instruction
whether or not any HHH ever aborts its emulation of DDD.
*THE TITLE OF THIS THREAD*
[The philosophy of computation reformulates existing ideas on a new basis ---]
- couterfactualYou can baselessly claim that verified facts are counter-factualYour statement was about a situation where "people fail to agree with
you cannot show this.
this and also fail to correctly point out any error". But that situation
has not happened as people have identified your errors (perhaps not all
but at least sufficiently many).
certainly not the slightest trace of any error when
examined within the philosophy of computation.It has always seemed quite ridiculous to me that everyoneThe currently received view that if you are asked "What is 5 + 6?"
here consistently construes the currently received view
as inherently infallible.
then only an answer that tells what 5 + 6 is is correct is infallible.
That 5 + 6 == 11 does seem infallibly true.
received view as infallible?
It is not clear at all unless you specify how those finiteI have known that equating believable with true is an errorThey call me stupid and ignorant for not accepting the currentlyYou are stupid if you regard your own view as infallible. If you
received view as inherently infallible.
regard something that has been tested and found good as infallible
then the risk of error can be small enough.
a great consequence ever since I was 14.
It seems clear that halt deciders must compute the mapping
from their input finite strings to the actual behavior
specified by these finite strings.
strings specify the actual behaviour.
language to make this 100% perfectly unequivocal.
A few lines of x86 code express complex algorithmsNo. Talking about something else does not refute.
succinctly enough that human minds are not totally
overwhelmed by far too much tedious detail.
It is not pspecifiedIn order for any machine to compute the mapping from
in the usual formulation of the problem. Also note that
the behaviour exists before those strings so "describe"
should be and usually is used instead of "specify". The
use of latter may give the false impression that the behaviour
is determined by those strings.
a finite string it must to so entirely on the basis
of the actual finite string and its specified semantics.
The finite string input to HHH specifies that HHH
MUST EMULATE ITSELF emulating DDD.
The finite string input to HHH1 specifies that HHH1
MUST NOT EMULATE ITSELF emulating DDD.
Unless HHH rejects its input DDD as non halting the
executed DDD never stops running. This itself proves
that HHH is correct and that DDD is not the same
instance as the one that HHH rejected.
The HP proofs are refuted by my work.It is true that when we construe the halting criteria asIt is true that doing that means leaving the halting proble unsolved.
requiring taking into account how a pathological relationship
changes the behavior of the input instead of simply ignoring
this behavior change that pathological inputs become decidable
as non-halting.
This is not quite the same ting as solving the halting problem.It is very far even from any thinking about the possibility to solve
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