Re: DD correctly emulated by HHH --- Totally ignoring invalid rebuttals ---PSR---

On 3/8/2025 9:03 AM, olcott wrote:

On 3/8/2025 2:47 AM, Fred. Zwarts wrote:

Op 08.mrt.2025 om 02:49 schreef olcott:

On 3/7/2025 10:25 AM, Fred. Zwarts wrote:

Op 07.mrt.2025 om 16:17 schreef olcott:

On 3/7/2025 2:59 AM, Fred. Zwarts wrote:

Op 06.mrt.2025 om 21:13 schreef olcott:

On 3/6/2025 3:13 AM, Fred. Zwarts wrote:

Op 06.mrt.2025 om 04:53 schreef olcott:

On 3/5/2025 9:31 PM, dbush wrote:

On 3/5/2025 10:17 PM, olcott wrote:

On 3/5/2025 7:10 PM, dbush wrote:

>
In other words, you know that what you're working on has nothing to do with the halting problem, but you don't care.

>
In other words I WILL NOT TOLERATE ANY BULLSHIT DEFLECTION.
You have proven that you know these things pretty well SO QUIT THE SHIT!
>

>
You want people to accept that HHH(DD) does in fact report that changing the code of HHH to an unconditional simulator and running HHH(DD) will not halt.
>

>
DD correctly emulated by HHH cannot possibly
reach its own "ret" instruction and terminate normally.

>
Yes, we agree that HHH fails to reach the 'ret' instruction,

>
Despicably dishonest attempt at the straw-man deception.
>

>
No rebuttal. So, we agree that HHH fails to reach the 'ret' instruction.

>
Not at all. Trying to get away with changing the subject
WILL NOT BE TOLERATED.
>

If you do not agree that HHH fails to reach the 'ret' instruction (that world-class simulators do reach, just as the direct execution does), show how it reaches the 'ret' instruction.

>
*set X*
When-so-ever any input to any simulating termination
analyzer calls the simulator that is simulating itself
>
*result of set X*
this input cannot possibly reach its own final state
and terminate normally because it remains stuck in
recursive emulation.
>

>
So, we agree that any simulator that tries to simulate *itself* cannot possibly reach the end of its simulation.

 Apparently you don't understand that inputs to a
simulating termination analyzer specifying infinite
recursion or recursive emulation cannot possibly
reach their own final state and terminate normally.

Apparently you don't understand that inputs to a termination analyzer, simulating or otherwise, are specified by the specification that is the halting function:
(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed
And HHH(DD)==0 fails to meet the above specification