Re: DD correctly emulated by HHH --- Totally ignoring invalid rebuttals ---PSR---

On 3/8/2025 6:56 PM, dbush wrote:

On 3/8/2025 7:29 PM, olcott wrote:

On 3/8/2025 5:31 PM, dbush wrote:

On 3/8/2025 6:23 PM, olcott wrote:

On 3/8/2025 4:58 PM, dbush wrote:

On 3/8/2025 5:42 PM, olcott wrote:

On 3/8/2025 9:00 AM, dbush wrote:

On 3/8/2025 9:03 AM, olcott wrote:

>
Apparently you don't understand that inputs to a
simulating termination analyzer specifying infinite
recursion or recursive emulation cannot possibly
reach their own final state and terminate normally.

>
Apparently you don't understand that inputs to a termination analyzer, simulating or otherwise, are specified by the specification that is the halting function:
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(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed
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And HHH(DD)==0 fails to meet the above specification

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*THIS IS A SEMANTIC TAUTOLOGY THUS IMPOSSIBLY FALSE*
Replacing the code of HHH with an unconditional simulator and subsequently running HHH(DD) cannot possibly reach
its own "ret" instruction and terminate normally
because DD calls HHH(DD) in recursive emulation.
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It is ridiculously stupid to believe that HHH must
report on behavior other than the above behavior.
>

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It must if it is to be classified as a halt decider or termination analyzer as per the definition.

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In other words you believe that HHH

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Is required to map the halting function to meet the requirements to be a halt decider / termination analyzer.
>

>
HHH must map from the input finite string DD
to the behavior that this finite string specifies

 And what it specifies, to be considered a solution to the halting problem, is given by the specification:
 Given any algorithm (i.e. a fixed immutable sequence of instructions) X described as <X> with input Y:
 A solution to the halting problem is an algorithm H that computes the following mapping:
 (<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed
 

In the same way that Sum(5,3) == 9
That is misconception is very widely held
does not make it not a misconception.
It is your above crazy nonsense that I require complete
agreement with these exact words before moving on to
any other point:
DD correctly emulated by HHH cannot possibly reach
its own "ret" instruction and terminate normally
because DD calls HHH(DD) in recursive emulation.
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer