Re: Every sufficiently competent C programmer knows --- posthumous reviewers

On 2025-03-13 20:56:22 +0000, olcott said:

On 3/13/2025 4:22 AM, Mikko wrote:

On 2025-03-13 00:36:04 +0000, olcott said:
 

 void DDD()
{
   HHH(DDD);
   return;
}
 int DD()
{
   int Halt_Status = HHH(DD);
   if (Halt_Status)
     HERE: goto HERE;
   return Halt_Status;
}
 When HHH correctly emulates N steps of the
above functions none of them can possibly reach
their own "return" instruction and terminate normally.

 Nevertheless, assuming HHH is a decider, Infinite_Loop and Infinite_Recursion
specify a non-terminating behaviour, DDD specifies a terminating behaviour

 _DDD()
[00002172] 55         push ebp      ; housekeeping
[00002173] 8bec       mov  ebp,esp  ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404     add  esp,+04
[00002182] 5d         pop  ebp
[00002183] c3         ret
Size in bytes:(0018) [00002183]
 What is the sequence of machine language
instructions of DDD emulated by HHH such that DDD
reaches its machine address 00002183?
 Any failure to answer with the sequence of machine
addresses will be construed as
YOU KNOW THAT YOU ARE LYING OR DON'T UNDERSTAND THE QUESTON

That a question is not answered is not a lie. That is unfortunate as if
iit were it would be much easier to point out that you are a liar. But
it isn't so we can only call you a liar when you actually say sometning.
If you really want to be called a liar when you don't answer some
question then say so and tell why so that we may try to find some
solution.
--
Mikko