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On 5/15/2024 6:16 AM, Richard Damon wrote:So, you ADMIT that Tarski is right.On 5/15/24 12:11 AM, olcott wrote:That is correctOn 5/13/2024 9:31 PM, Richard Damon wrote:>On 5/13/24 10:03 PM, olcott wrote:>On 5/13/2024 7:29 PM, Richard Damon wrote:No, so True(L, p) is false>>
Remember, p defined as ~True(L, p) is BY DEFINITION a truth bearer, as True must return a Truth Value for all inputs, and ~ a truth valus is always the other truth value.
>
Can a sequence of true preserving operations applied to expressions
that are stipulated to be true derive p?
and thus ~True(L, p) is true.
>>>
Can a sequence of true preserving operations applied to expressions
that are stipulated to be true derive ~p?
No, so False(L, p) is false,
>
*PLEASE STUDY THIS VERY CAREFULLY SO WE DON'T HAVE TO KEEP*
*GOING OVER THE EXACT SAME POINT MY SHOULDER IS HURTING*
>
On 5/14/2024 10:44 PM, Richard Damon wrote:
> So, what result SHOULD True(L, x) return? when x is
> the expression ~True(L, x)
>
>
*YOU ALREADY AGREED THAT*
>
On 5/13/2024 9:31 PM, Richard Damon wrote:
> No, so True(L, p) is false
>
*WHEN*
>
>> On 5/13/2024 7:29 PM, Richard Damon wrote:
>>> ... p defined as ~True(L, p) ...
>
>
So, if x being true is defined as there exists a sequence of truth perserving operations to the truth makes, false needs to be defined as a similar sequence of operations to ~x. (or is this not true an ~ isn't always defined?)
>
So, the True predicate can't correctly say True(L, x) is either, so its result must be that it is a "non-truth-bearer"
But that is the DEFINITION of a predicate.and thus True can not be a predicate.No that is incorrect.
>
x = "a fish"In other words, you don't understand the issue because you are just too dense.
True(English, x) == false
False(English, x) == false
x is a type mismatch error for any formal system of bivalent logic thus
cannot be an expression stipulated to be true or derived by applying
truth preserving operations to expressions stipulated to be true.
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