Re: Can D simulated by H terminate normally? --- Message_ID Provided

On 5/18/24 5:00 PM, olcott wrote:

On 5/18/2024 3:02 PM, Richard Damon wrote:

On 5/18/24 3:57 PM, olcott wrote:

On 5/1/2024 7:10 PM, Richard Damon wrote:

The second method uses the fact that you have not restricted what H is allowed to do, and thus H can remember that it is simulating, and if a call to H shows that it is currently doing a simulation, just immediately return 0.

>
Nice try but this has no effect on any D correctly simulated by H.
When the directly executed H aborts its simulation it only returns
to whatever directly executed it.

>
Why? My H does correctly simulate the D it was given.
>
You don't seem to understand how the C code actually works.
>

>
If the directly executed outermost H does not abort then none of
the inner simulated ones abort because they are the exact same code.
When the directly executed outermost H does abort it can only return
to its own caller.

>
WHAT inner simulatioin?
>
>
My H begins as:
>
int H(ptr x, ptr y) {
   static int flag = 0;
   if(flag) return 0;
   flag = 1;
>
followed by essentially your code for H, except that you need to disable the hack that doesn't simulate the call to H, but just let it continue into H where it will immediately return to D and D will then return.
>
>

 My original H(P,P) does simulate itself simulating P.

But not your current one per you repository.

 We are talking about every element of an infinite set where
H correctly simulates 1 to ∞ steps of D thus including 0 to ∞
recursive simulations of H simulating itself simulating D.
 At whatever point the directly executed H(D,D) stops simulating
its input it cannot possibly return to any simulated input.
 

No, we are talking about ONE of those elements being able to do what you said NONE of the elements could do.
I guess you are just admitting you don't understand what the meaning of the various categorical conditions you use mean.
Your claim is that NONE of that infinite set could simulate D past the call H.
I showed one that does.