Liste des Groupes | Revenir à theory |
On 5/18/24 6:47 PM, olcott wrote:Yes we must build from mutual agreement, good.On 5/18/2024 5:22 PM, Richard Damon wrote:So, for a statement x to be false, it says that there must be a sequence of truth perserving operations that derive ~x from, right?On 5/18/24 4:00 PM, olcott wrote:>On 5/18/2024 2:57 PM, Richard Damon wrote:>On 5/18/24 3:46 PM, olcott wrote:>On 5/18/2024 12:38 PM, Richard Damon wrote:>On 5/18/24 1:26 PM, olcott wrote:>On 5/18/2024 11:56 AM, Richard Damon wrote:>On 5/18/24 12:48 PM, olcott wrote:On 5/13/2024 9:31 PM, Richard Damon wrote:On 5/18/2024 9:32 AM, Richard Damon wrote:>On 5/18/24 10:15 AM, olcott wrote:>On 5/18/2024 7:43 AM, Richard Damon wrote:>No, your system contradicts itself.>
>
You have never shown this.
The most you have shown is a lack of understanding of the
Truth Teller Paradox.
No, I have, but you don't understand the proof, it seems because you don't know what a "Truth Predicate" has been defined to be.
>
My True(L,x) predicate is defined to return true or false for every
finite string x on the basis of the existence of a sequence of truth
preserving operations that derive x from
And thus, When True(L, p) established a sequence of truth preserving operations eminationg from ~True(L, p) by returning false, it contradicts itself. The problem is that True, in making an answer of false, has asserted that such a sequence exists.
>
> On 5/13/24 10:03 PM, olcott wrote:
>> On 5/13/2024 7:29 PM, Richard Damon wrote:
>>>
>>> Remember, p defined as ~True(L, p) ...
>>
>> Can a sequence of true preserving operations applied
>> to expressions that are stipulated to be true derive p?
> No, so True(L, p) is false
>>
>> Can a sequence of true preserving operations applied
>> to expressions that are stipulated to be true derive ~p?
>
> No, so False(L, p) is false,
>
>
*To help you concentrate I repeated this*
The Liar Paradox and your formalized Liar Paradox both
contradict themselves that is why they must be screened
out as type mismatch error non-truth-bearers *BEFORE THAT OCCURS*
And the Truth Predicate isn't allowed to "filter" out expressions.
>
YOU ALREADY KNOW THAT IT DOESN'T
WE HAVE BEEN OVER THIS AGAIN AND AGAIN
THE FORMAL SYSTEM USES THE TRUE AND FALSE PREDICATE
TO FILTER OUT TYPE MISMATCH ERROR
>
The first thing that the formal system does with any
arbitrary finite string input is see if it is a Truth-bearer:
Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
No, we can ask True(L, x) for any expression x and get an answer.
>
The system is designed so you can ask this, yet non-truth-bearers
are rejected before True(L, x) is allowed to be called.
>
>
>
Not allowed.
>
My True(L,x) predicate is defined to return true or false for every
finite string x on the basis of the existence of a sequence of truth
preserving operations that derive x from
>
A set of finite string semantic meanings that form an accurate
verbal model of the general knowledge of the actual world that
form a finite set of finite strings that are stipulated to have
the semantic value of Boolean true.
>
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>
>
So do you still say that for p defined in L as ~True(L, p) that your definition will say that True(L, p) will return false?It is the perfectly isomorphic to this:
That means that the predicate establishes that there IS a seriers of truth perservion operations that derive the expreson ~True(L, p).You keep confusing:
And if so, doesnt that mean that the truth value of p will be true, since p is defined as the logical negation of True(L, p), which we just establish HAS a sequence of truth perservion operations as indicated by the truth predicate.In Prolog both the Liar Paradox and the Truth Teller Paradox
and if so, doesn't that mean that your True(L, x) just returned the false value for an input that was, by your definitions, true?It must work the same as Prolog and detect cycles
How does that work?
Deflect again and I will just point out that you have refused to answer because you are just admitting you can't figure out how to fix your broken system.--
After all, you have proven that just because you thinkl something is self-evedently true, doesn't mean that it is true, as you sense of self-evedent is just broken.
Les messages affichés proviennent d'usenet.