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Le 07/06/2024 à 21:36, olcott a écrit :SHOULD IO REPEAT THIS FIFTY TIMES SO THAT YOU NOTICE THAT I SAID IT AT LEAST ONCE?On 6/7/2024 2:28 PM, Richard Damon wrote:There is NO definition of "correct simulation" above.On 6/7/24 2:41 PM, olcott wrote:>On 6/7/2024 1:24 PM, Richard Damon wrote:>On 6/7/24 2:02 PM, olcott wrote:>On 6/7/2024 12:50 PM, Alan Mackenzie wrote:>[ Followup-To: set ]>
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In comp.theory olcott <polcott333@gmail.com> wrote:
>
[ .... ]
>_DD()>
[00001e12] 55 push ebp
[00001e13] 8bec mov ebp,esp
[00001e15] 51 push ecx
[00001e16] 8b4508 mov eax,[ebp+08]
[00001e19] 50 push eax ; push DD
[00001e1a] 8b4d08 mov ecx,[ebp+08]
[00001e1d] 51 push ecx ; push DD
[00001e1e] e85ff5ffff call 00001382 ; call HHA {correct simulation} means that each instruction of the>
above x86 machine language of DD is correctly simulated
by HH and simulated in the correct order.
That's a bit of sudden and substantial change, isn't it? Less than a few
days ago, you were defining a correct simulation as "1 to N instructions"
simulated (without ever specifying what you meant by N). It seems that
the simulation of exactly one instruction would have met your criterion.
>
That now seems to have changed.
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Because I am a relatively terrible writer I must constantly
improve my words on the basis of reviews.
>
Try to show how this DD correctly simulated by any HH ever
stops running without having its simulation aborted by HH.
>
_DD()
[00001e12] 55 push ebp
[00001e13] 8bec mov ebp,esp
[00001e15] 51 push ecx
[00001e16] 8b4508 mov eax,[ebp+08]
[00001e19] 50 push eax ; push DD
[00001e1a] 8b4d08 mov ecx,[ebp+08]
[00001e1d] 51 push ecx ; push DD
[00001e1e] e85ff5ffff call 00001382 ; call HH
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A {correct simulation} means that each instruction of the
above x86 machine language of DD is correctly simulated
by HH and simulated in the correct order.
>
Anyone claiming that HH should report on the behavior
of the directly executed DD(DD) is requiring a violation
of the above definition of correct simulation.
>
And thus you admit that HH is not a Halt Decider,
More dishonest deflection.
The point that I made and you try to deflect using the strawman
deception as a fake rebuttal is the I just proved that DD is correctly
simulated by HH and this is not the same behavior as the directly
executed DD(DD).
>
And thus, your idea of "Correct Simulation" fails to meet the fundamental definition of the Correct Simulaiton of the machine.
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Liar Liar pants on fire. I truly hope that this does not send you
to Hell. Maybe are are in one of those groups that believes salvation
can never be lost no matter what one's future behavior is.
>
I myself would not risk that.
>
Try to show how this DD correctly simulated by any HH ever
stops running without having its simulation aborted by HH.
>
_DD()
[00001e12] 55 push ebp
[00001e13] 8bec mov ebp,esp
[00001e15] 51 push ecx
[00001e16] 8b4508 mov eax,[ebp+08]
[00001e19] 50 push eax ; push DD
[00001e1a] 8b4d08 mov ecx,[ebp+08]
[00001e1d] 51 push ecx ; push DD
[00001e1e] e85ff5ffff call 00001382 ; call HH
>
A {correct simulation} means that each instruction of the
above x86 machine language of DD is correctly simulated
by HH and simulated in the correct order.
>
Anyone claiming that HH should report on the behavior
of the directly executed DD(DD) is requiring a violation
of the above definition of correct simulation.
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