Re: 197 page execution trace of DDD correctly simulated by HHH

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Sujet : Re: 197 page execution trace of DDD correctly simulated by HHH
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : comp.theory
Date : 02. Jul 2024, 04:24:30
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <v5vocu$1oanb$10@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32
User-Agent : Mozilla Thunderbird
On 7/1/24 9:36 PM, olcott wrote:
On 7/1/2024 7:38 PM, Richard Damon wrote:
On 7/1/24 8:59 AM, olcott wrote:
On 7/1/2024 3:23 AM, Fred. Zwarts wrote:
Op 30.jun.2024 om 19:20 schreef olcott:
>
_DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
>
>
It cannot possibly return, because HHH aborts itself one cycle too early, showing that the emulation is incorrect. If that is over your head, try to learn how x86 instructions work.
>
_DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
>
DDD is correctly emulated by HHH which calls an
emulated HHH(DDD) to repeat the process until aborted.
>
>
>
CAN'T BE.
>
A "Correct Emulation" is one that produces the same result as the program at the input.
>
 Which can only possibly occur be disregarding the semantics
of the x86 language. Liars would do that ignoramuses would do
that. Everyone with the equivalent of a BSCS would know that
what I said is true.
 
Why do you say that? That is EXACTLY the definition of Correct Emulation. You need to EXACTLY EMULATE EACH AND EVERY instrucgtion , in the order they will be executed when the program is run.
That WILL produce the exact behavior of running the program.
The PARTIAL emulation done by the decider only show SOME of the behavior that is in the input.
You have been asked, and still fail to point out, which instruction when correctly emulated exactly by the semantics of the x86 language result in a difference between the correct emulation by HHH and the actual exectuion of DDD?
The answer, NONE of them. HHH Just need to stop emulating, and not see the full behavior, or it will form a DIFFERENT input that makes that HHH not halt.
You don't even seem to understand the determinism of program behavior.

Date Sujet#  Auteur
10 Nov 24 o 

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