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On 7/1/2024 6:08 AM, Richard Damon wrote:The behaviour specified by DDD is whatever it is, and does not depend onOn 6/30/24 10:27 PM, olcott wrote:When DDD is no longer being emulated all of its behaviorOn 6/30/2024 9:16 PM, Richard Damon wrote:The emulation stops, and the emulating behavor of HHH stops, but not the behavior of the input.On 6/30/24 9:38 PM, olcott wrote:How can stopping the emulation the first fourOn 6/30/2024 8:24 PM, Richard Damon wrote:And, since the HHH that DDD calls will abort is emulation, it WILL return to DDD and it will return also.On 6/30/24 9:03 PM, olcott wrote: >> On 6/30/2024 7:44 PM, Richard Damon wrote:I don't understand why you so stupidly lie about this.I had to dumb this down because even the smartestBut that is NOT the "behavior of the input", and CAN NOT BE SO DEFINED.
people here were overwhelmed:
The call from DDD to HHH(DDD) when N steps of DDD are
correctly emulated by any pure function x86 emulator
HHH at machine address 0000217a cannot possibly return.
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
DDD is correctly emulated by HHH which calls an
emulated HHH(DDD) to repeat the process until aborted.
instructions of DDD possibly do anything besides stop?
stops. DDD is the input.
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