Re: DDD correctly emulated by HHH is Correctly rejected as non-halting V2

On 7/12/2024 6:41 PM, Richard Damon wrote:

On 7/12/24 7:19 PM, olcott wrote:

On 7/12/2024 5:56 PM, Richard Damon wrote:

On 7/12/24 10:56 AM, olcott wrote:

Thus each HHH element of the above infinite set of HHH/DDD pairs is
necessarily correct to reject its DDD as non-halting.
>

Nope.
NONE Of them CORRECTLY rejected itS DDD as non-halting and you are
shown to be ignorant of what you are talking about.
The HHH that did a partial emulation got the wrong answer, because
THEIR DDD will halt. and the HHH that doen't abort never get around
to rejecting its DDD as non-halting.

>
When no DDD of every HHH/DDD that can possibly exist halts then each
HHH that rejects its DDD as non-halting is necessarily correct.
*No double-talk and weasel words can overcome that*
>

Which is just your double-talk to try to redefine what halting means.
 

You try to cut my airtight proof up in little pieces and fail. Every
rebuttal that you make has disagreeing with the semantics of the x86
language as its basis.