Re: What is the correct halt status for HHH(DDD) ?

On 7/14/2024 3:00 AM, Mikko wrote:

On 2024-07-13 18:15:35 +0000, olcott said:
 

On 7/13/2024 12:25 PM, Richard Damon wrote:

On 7/13/24 12:48 PM, olcott wrote:

What is the correct halt status for an input to
a simulating termination analyzer that calls its
own termination analyzer?
 typedef void (*ptr)();
int HHH(ptr P);
 void DDD()
{
   HHH(DDD);
}
 int main()
{
   HHH(DDD);
}
 

 Halting.
 Since HHH defined to be a termination analyzer, by that definition it must return to its caller.
 Since DDD has no inputs, its behavior isn't affected by any inputs, and thus DDD will halt for ALL input conditions, so

 You are stupidly saying that Infinite_Loop() will halt because
it has no inputs.

 

void Infinite_Loop()
{
   HERE: goto HERE;
}

 You are stupidly saying that Infinite loop is executed as a part of HHH.
 

 Infinite_Loop() is emulated in its own process context.