Liste des Groupes | Revenir à theory |
On 2024-07-15 03:41:24 +0000, olcott said:No that is wrong. The finite string must encode a Turing machine.
On 7/14/2024 9:04 PM, Richard Damon wrote:That's right. But the finite string can be a description of a Turing machine.On 7/14/24 9:27 PM, olcott wrote:Turing machines only operate on finite strings they do>>
Any input that must be aborted to prevent the non termination
of simulating termination analyzer HHH necessarily specifies
non-halting behavior or it would never need to be aborted.
Excpet, as I have shown, it doesn't.
>
Your problem is you keep on ILEGALLY changing the input in your argument because you have misdefined what the input is.
>
The input to HHH is ALL of the memory that it would be accessed in a correct simulation of DDD, which includes all the codd of HHH, and thus, if you change HHH you get a different input.
>
If you want to try to claim the input is just the bytes of the function DDD proper then you are just admitting that you are nothing more than a lying idiot that doesn't understand the problem,
not operate on other Turing machines *dumbo*
That way a Turing machine can say someting about another Turing machine,Not exactly. It can only report on the behavior that the input
evenAll of the questions that a TM cannot answer are logical
simulate its complete execution. Or it can count something simple like the
number of states or the set of symbols that the described Turing machine may
write but not erase. But there are questions that no Turing machine can
answer from a description of another Turing machine.
Les messages affichés proviennent d'usenet.