Re: Who here understands that the last paragraph is Necessarily true? --- Honest Dialogue

On 7/20/24 10:23 AM, olcott wrote:

On 7/20/2024 3:53 AM, Fred. Zwarts wrote:

Op 19.jul.2024 om 16:49 schreef olcott:

>
void Infinite_Loop()
{
   HERE: goto HERE;
}
>
int main()
{
   HHH(Infinite_Loop);
}
>

>
Irrelevant, because you do not understand the difference between Infinite_Loop and Finite_Recursion.
>

 *Until you understand that this is true*
*we cannot have an honest dialogue*

Until you understand that you logic defies the meaning of the words, you won't get anywhere.

 _DDD()
[00002163] 55         push ebp      ; housekeeping
[00002164] 8bec       mov ebp,esp   ; housekeeping
[00002166] 6863210000 push 00002163 ; push DDD
[0000216b] e853f4ffff call 000015c3 ; call HHH(DDD)
[00002170] 83c404     add esp,+04
[00002173] 5d         pop ebp
[00002174] c3         ret
Size in bytes:(0018) [00002174]
 int main()
{
   DDD();
}
 Calls HHH(DDD) that must abort the emulation of its input
or {HHH, emulated DDD and executed DDD} never stop running.
 

Right, and because HHH thus DOES abort its emulation of DDD, that makes the DDD that calls it, and thus ALL DDD non-halting programs.
HHH, by definition, does what HHH does, and thus asking what would happen to a different input is irrelevent.
Of course, part of your problem is you claimed desription of DDD is in fact just a LIE as it doesn't include all the code of DDD, so you are just LYING that your DDD, as represented, is a program to decide on.
All you are proving is your utter stupidity and ignorance of what you talk about, and that you have decided to make yourself in to a pathological liar.
You system which ties the decider to the input just breaks the logic you want to use.