Liste des Groupes | Revenir à theory |
On 7/23/24 2:12 PM, olcott wrote:When the halting problem is defined as providing the haltOn 7/23/2024 12:38 PM, Alan Mackenzie wrote:and (a) is wrong because it says that DDD doesn't halt when it does.olcott <polcott333@gmail.com> wrote:>On 7/23/2024 2:26 AM, Mikko wrote:>On 2024-07-22 16:10:55 +0000, olcott said:>On 7/20/2024 3:03 PM, Alan Mackenzie wrote:[ Followup-To: set ]>In comp.theory Fred. Zwarts <F.Zwarts@hetnet.nl> wrote:>[ .... ]>Olcott could not point to an error, but prefers to ignore it. So, I
will
repeat it, until either an error is found, or olcott admits that HHH
cannot possibly simulate itself correctly.>This has the disadvantage of making your posts boring to read. All but
one poster on this newsgroup KNOW that Olcott is wrong, here.>Continually repeating your argument won't get him to admit he's wrong.
Richard has been trying that for much longer than you have, with the
same lack of success. Olcott's lack of capacity for abstract reasoning,
combined with his ignorance, combined with his arrogance, prevent him
learning at all.>May I suggest that you reconsider your strategy of endless repetition?>Thanks!
>
>>Rebuttals like yours are entirely baseless by failing to point out any
mistake.>What makes you think taht Alan Mackenzie was trying to rebut what
Fred. Zwarts had said?
>In other words you don't see the ad hominem attacks against>
me that are listed above?
What, exactly, is wrong with what you call my "ad hominem attacks"? In
most of what you write on this group you are objectively wrong,
*No as many as one person ever actually showed that*
>
void DDD()
{
HHH(DDD);
}
>
int main()
{
HHH(DDD);
}
>
Of the two hypothetical possible ways that HHH can be encoded:
(a) HHH(DDD) is encoded to abort its simulation at some point.
(b) HHH(DDD) is encoded to never abort its simulation.
>
We can know that (b) is wrong because this fails to meet the design requirement that HHH must itself halt.
Les messages affichés proviennent d'usenet.