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Am Thu, 01 Aug 2024 10:50:29 -0500 schrieb olcott:On 8/1/2024 10:44 AM, joes wrote:Am Thu, 01 Aug 2024 08:04:23 -0500 schrieb olcott:When one disables the abort code then the cycle never stops.On 8/1/2024 7:56 AM, Fred. Zwarts wrote:I mean, how many iterations of an infinite loop can I skip simulatingOp 01.aug.2024 om 13:51 schreef olcott:Only a freaking moron would believe that a non terminating inputOn 8/1/2024 2:46 AM, Fred. Zwarts wrote:But since HHH deviates from the semantics of the x86 language (byOp 01.aug.2024 om 05:51 schreef olcott:When HHH does what-ever-the-hell the x86 semantics specifies thenOn 7/31/2024 10:08 PM, wij wrote:But a correct simulation is impossible.On Tue, 2024-07-30 at 18:50 -0500, olcott wrote:If DDD correctly emulated by HHH cannot possibly reach its return>But how do you determine it is non-halting?
It is not supposed to be a general solution to the halting
problem.
it only shows how the "impossible" input is correctly determined
to be non halting.
As I know you are even unable to define what 'halt' mean !!!
instruction then it never halts.
HHH is correct.
skipping instructions of a halting program) it is incorrect.
should be simulated forever.
or how many do I have to simulate to get identical behaviour?
When one introduces it, it becomes unnecessary, because the cycle stopsUnless the outside aborts infinite execution occurs.
from the INSIDE.
After how many repetitions can infinite recursion be aborted beforeAn infinite computation can never be completed.
the simulation becomes wrong?
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