Sujet : Re: HHH maps its input to the behavior specified by it --- never reaches its halt state ---
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 09. Aug 2024, 21:53:12
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v95vjo$60of$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
User-Agent : Mozilla Thunderbird
On 8/9/2024 2:35 PM, Fred. Zwarts wrote:
Op 09.aug.2024 om 18:19 schreef olcott:
void DDD()
{
HHH(DDD);
return;
}
Each HHH of every HHH that can possibly exist definitely
emulates zero to infinity instructions of DDD correctly.
Every expert in the C language sees that this emulated DDD
cannot possibly reaches its own "return" instruction halt state.
Each element of this set corresponds to one element of
the set of positive integers indicating the number of
x86 instructions of DDD that it emulates.
When we look at every HHH that can possibly exist then
we see that DDD correctly emulated by each one of these
cannot possibly reach its "return" instruction halt state.
Your own words were that HHH is a halting decider. You even showed traces of HHH aborting after two cycles. Are you short of memory, or are you lying? Or are you again substituting your dreams of a non-aborting non-halting HHH for facts?
The post is intended to stand on its own thus forming
a rebuttal to this post based on whet I said in some
other post is the strawman deception.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer