Sujet : Re: HHH maps its input to the behavior specified by it --- never reaches its halt state ---
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theoryDate : 10. Aug 2024, 14:01:00
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v97kps$kof0$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
User-Agent : Mozilla Thunderbird
On 8/10/2024 6:48 AM, Richard Damon wrote:
On 8/10/24 7:34 AM, olcott wrote:
On 8/10/2024 3:27 AM, Fred. Zwarts wrote:
Op 09.aug.2024 om 22:53 schreef olcott:
On 8/9/2024 2:35 PM, Fred. Zwarts wrote:
Op 09.aug.2024 om 18:19 schreef olcott:
>
void DDD()
{
HHH(DDD);
return;
}
>
Each HHH of every HHH that can possibly exist definitely
emulates zero to infinity instructions of DDD correctly.
Every expert in the C language sees that this emulated DDD
cannot possibly reaches its own "return" instruction halt state.
And you don't need to be an expert to see that this proves that all these simulations are incorrect.
>
In other words you are trying to get away with the lie that
Richard has been persistently pushing:
>
When N > 0 instructions of DDD are correctly emulated by HHH
then no instructions of DDD have been correctly emulated.
>
No, that is just a lie you say about me.
Your deceptive words confuse even you?
If the only correct simulation is a compete simulation that entails
this:
When N > 0 instructions of DDD are correctly emulated by HHH
then no instructions of DDD have been correctly emulated.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
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