Liste des Groupes | Revenir à theory |
On 8/14/2024 3:56 PM, Mike Terry wrote:A correct emulation of DDD by HHH is only correctly judgedOn 14/08/2024 18:45, olcott wrote:*You corrected Joes most persistent error*On 8/14/2024 11:31 AM, joes wrote:>Am Wed, 14 Aug 2024 08:42:33 -0500 schrieb olcott:>On 8/14/2024 2:30 AM, Mikko wrote:What do we care about a complete simulation? HHH isn't doing one.On 2024-08-13 13:30:08 +0000, olcott said:A complete emulation is not required to correctly predict that aOn 8/13/2024 6:23 AM, Richard Damon wrote:>On 8/12/24 11:45 PM, olcott wrote:A complete emulation of a non-terminating input has always been a>Which is only correct if HHH actuallly does a complete and correct
*DDD correctly emulated by HHH cannot possibly reach its* *own
"return" instruction final halt state, thus never halts*
>
emulation, or the behavior DDD (but not the emulation of DDD by HHH)
will reach that return.
>
contradiction in terms.
HHH correctly predicts that a correct and unlimited emulation of DDD
by HHH cannot possibly reach its own "return" instruction final halt
state.
That is not a meaningful prediction because a complete and unlimited
emulation of DDD by HHH never happens.
>
complete emulation would never halt.
>
Please go read how Mike corrected you.
>
Lol, dude... I mentioned nothing about complete/incomplete simulations.
>
She made sure to ignore this correction.
But while we're here - a complete simulation of input D() would clearly halt._DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
A complete simulation *by HHH* remains stuck in
infinite recursion until aborted.
Termination analyzers / halt deciders are only required
to correctly predict the behavior of their inputs.
Termination analyzers / halt deciders are only required
to correctly predict the behavior of their inputs, thus
the behavior of non-inputs is outside of their domain.
*This make the words you say below moot*
--You have seen that yourself, e.g. with main() calling DDD(), or UTM(DDD), or HHH1(DDD). [All of those simulate DDD to completion and see DDD return. What I said earlier was that HHH(DDD) does not simulate DDD to completion, which I think everyone recognises - it aborts before DDD() halts.
>
>
Mike.
>
Les messages affichés proviennent d'usenet.