Re: Anyone that claims this is not telling the truth

On 8/17/24 5:05 PM, olcott wrote:

On 8/17/2024 4:00 PM, Richard Damon wrote:

On 8/17/24 4:41 PM, olcott wrote:

On 8/17/2024 3:20 PM, Richard Damon wrote:

On 8/17/24 4:10 PM, olcott wrote:

On 8/17/2024 2:27 PM, Richard Damon wrote:
 > On 8/17/24 3:00 PM, olcott wrote:>> On 8/17/2024 1:50 PM, Richard Damon wrote:
 >>>>>> And thus ALL of memory is part of the input,

>
Any additional details have no effect what-so-ever on my claim.
>

>
Suure it does.
>
Since your argument tries to say that since DDD is the same to all of them, so its the behavior.
>
You are just admitting to being a LIAR.
>

>
*Calling me a liar admits that insults is all that you have*
*If I made a mistake then show that*

>
I did.
>

>
FOR THREE YEARS YOU ALWAYS CHEAT
BY CHANGING MY WORDS AND REBUTTING THESE CHANGED WORDS
>
*Everything that is not expressly stated below is*
*specified as unspecified*

>
Ok.
>

>
void DDD()
{
   HHH(DDD);
}
>
_DDD()
[00002172] 55         push ebp      ; housekeeping
[00002173] 8bec       mov ebp,esp   ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404     add esp,+04
[00002182] 5d         pop ebp
[00002183] c3         ret
Size in bytes:(0018) [00002183]
>
*It is a basic fact that DDD emulated by HHH according to*
*the semantics of the x86 language cannot possibly stop*
*running unless aborted* (out of memory error excluded)
>

>
No, DDD can NOT be emulated accoreding to the semantics of the x86 langauge, because the contents of the location 000015d2 is not provided to be emulated, and will need to be emulated after emulating the call instruction.
>

>
Everything that is logically entailed by the above specification
is included by reference. The assumption that DDD and HHH were
not in the same memory space has always been ridiculous.
>

>
Then I guess you accept that every different HHH generates a DIFFERENT Input, as that input, BY LOGHICAL NECESSITY includes all the code of HHH so it can be emulated, and thus you claims that "All the DDDs have the same bytes" is just a blantent lie.
>

 This is my only claim
*It is a basic fact that DDD emulated by HHH according to*
*the semantics of the x86 language cannot possibly stop*
*running unless aborted* (out of memory error excluded)
 I am not claiming anything about any bytes.
 

And, as I point out, that isn't true if HHH ever aborts its simulation.
SO, eitehr you accept that this only holds for PURE EMULATORS that NEVER abort, or you accept that you statement is just untrue.
As I often do, I look ahead at what you are going to claim in the future and cut you off at the pass to put up front, the limits of what I am saying,