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On 8/17/2024 10:30 AM, Richard Damon wrote:Now you switched the topic. Earlier you were not talking about x86utmOn 8/17/24 11:09 AM, olcott wrote:No it has moved up to a ridiculous and utterlyOn 8/17/2024 10:06 AM, Richard Damon wrote:How do you emulate dthe CALL HHH instruction without the code that follows?On 8/17/24 10:58 AM, olcott wrote:You are not going to get very far with any claim thatOn 8/17/2024 9:10 AM, Richard Damon wrote:To say that DDD is emulated by HHH means that it must be possible to validly do that act.On 8/17/24 8:29 AM, olcott wrote:You are inserting a word that I did not say.void DDD()No, anyone saying that the above is something that CAN be correctly emulated by the semantics of the x86 language is just a LIAR.
{
HHH(DDD);
}
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
*It is a basic fact that DDD emulated by HHH according to*
*the semantics of the x86 language cannot possibly stop*
*running unless aborted* (out of memory error excluded)
emulating a sequence of x86 machine-code bytes is impossible.
Who is the silly one now?
baseless false assumption that is directly contradicted
by the verified fact that x86utm takes Halt7.obj as
its input data, thus having all of the machine code
of HHH directly available to DDD.
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