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On 8/19/2024 2:36 AM, Mikko wrote:How does that formula contradict the original version?On 2024-08-18 12:32:54 +0000, olcott said:I appended the above formula
On 8/17/2024 7:29 AM, olcott wrote:What was wrong in the original version?void DDD()X = DDD emulated by HHH according to the semantics of the x86 language
{
HHH(DDD);
}
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
*It is a basic fact that DDD emulated by HHH according to*
*the semantics of the x86 language cannot possibly stop*
*running unless aborted* (out of memory error excluded)
Y = HHH never aborts its emulation of DDD
Z = DDD never stops running
(X ∧ Y) ↔ Z
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