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On 8/30/2024 3:11 AM, Mikko wrote:WHERE?On 2024-08-29 17:53:44 +0000, olcott said:The behavior of
>I just proved that the basic notion of finite strings>
having unique meanings independently of their context
is incorrect.
The context is the halting problem.
the directly executed DDD and executed HHH
is different from the behavior of
the emulated DDD and the emulated HHH
and all four of them are emulated by the worldSo why does HHH not show the CORRECT emulation of the call HHH instruction?
class x86 emulator libx86emu
It is easy to see that when the executed HHH emulates
DDD that it does this correctly when we look at the
execution trace and see the the first four instructions
of DDD are listed.
_DDD()But the following is *NOT* the "correct emulation" of the instruction above.
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
New slave_stack at:1038c4
Begin Local Halt Decider Simulation Execution Trace Stored at:1138cc
[00002172][001138bc][001138c0] 55 push ebp ; housekeeping
[00002173][001138bc][001138c0] 8bec mov ebp,esp ; housekeeping
[00002175][001138b8][00002172] 6872210000 push 00002172 ; push DDD
[0000217a][001138b4][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
New slave_stack at:14e2ecNope, just proves you don't know the meaning of the words you use, and that you are so stupid you can not learn them.
[00002172][0015e2e4][0015e2e8] 55 push ebp ; housekeeping
[00002173][0015e2e4][0015e2e8] 8bec mov ebp,esp ; housekeeping
[00002175][0015e2e0][00002172] 6872210000 push 00002172 ; push DDD
[0000217a][0015e2dc][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
Local Halt Decider: Infinite Recursion Detected Simulation Stopped
Then this emulated DDD calls an emulated HHH(DDD).
It is easy to see that when the executed HHH emulates
itself emulated DDD that it does this correctly when we
look at the execution trace and see the the first four
instructions of DDD are listed again.
It specifies the meanings
but not any finite strings to carry these meanings. The meanings
exist independently of any finite string. A solution or a partial
solution to the problem specifies how each of these meanings shall
be expressed with a finite string for other parts of the solution.
>
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