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On 9/4/2024 4:50 AM, Fred. Zwarts wrote:THe one at 00015d2.Op 03.sep.2024 om 15:29 schreef olcott:>> What instruction of DDD do you believe comes next?On 9/3/2024 2:15 AM, Fred. Zwarts wrote:>Op 03.sep.2024 om 00:22 schreef olcott:On 9/2/2024 12:52 PM, Fred. Zwarts wrote:>Op 02.sep.2024 om 18:38 schreef olcott:>A halt decider is a Turing machine that computes>
the mapping from its finite string input to the
behavior that this finite string specifies.
>
If the finite string machine string machine
description specifies that it cannot possibly
reach its own final halt state then this machine
description specifies non-halting behavior.
>
A halt decider never ever computes the mapping
for the computation that itself is contained within.
>
Unless there is a pathological relationship between
the halt decider H and its input D the direct execution
of this input D will always have identical behavior to
D correctly simulated by simulating halt decider H.
>
*Simulating Termination Analyzer H Not Fooled by Pathological Input D*
https://www.researchgate.net/ publication/369971402_Simulating_Termination_Analyzer_H_is_Not_Fooled_by_Pathological_Input_D
>
A correct emulation of DDD by HHH only requires that HHH
emulate the instructions of DDD** including when DDD calls
HHH in recursive emulation such that HHH emulates itself
emulating DDD.
Indeed, it should simulate *itself* and not a hypothetical other HHH with different behaviour.
If HHH includes code to see a 'special condition' and aborts and halts, then it should also simulate the HHH that includes this same code and
>
DDD has itself and the emulated HHH stuck in recursive emulation.
>
void DDD()
{
HHH(DDD);
return;
}
It is not DDD. It is HHH that has the problem when trying to simulate itself.
Olcott removed the proof that I am right:
>
int main() {
return HHH(main);
}
>
where HHH halts, but claims that it does not halt. No DDD needed to prove that HHH reports false negatives.
>
Since he cannot prove that I am wrong, he thinks an ad hominem attack will help.
>>>
It does this correctly yet beyond your intellectual capacity.
>
Then he shows again the 'trace' of an incorrect simulation.
>_DDD()>
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
>
Instructions from machine address 00002172 through
machine address 0000217a are emulated.
>
What instruction of DDD do you believe comes next?
Assuming a correct simulation:
The next instruction would be that at 000015d2 in HHH.
What instruction
of DDD
of DDD
of DDD
of DDD
of DDD
do you believe comes next?
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