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On 9/6/2024 4:24 AM, Fred. Zwarts wrote:That has been told now several times. A correct simulation (as by HHH1, or the unmodified world class simulator) show that the next instruction is at 000015d2 (in HHH) and when HHH returns the next instruction in DDD is 0000217f, 00002182, 00002183 and DDD halts.Op 05.sep.2024 om 19:17 schreef olcott:CORRECT MEANS DO WHATEVER THE X86 CODE SAYSOn 9/5/2024 11:56 AM, joes wrote:>Am Thu, 05 Sep 2024 11:52:04 -0500 schrieb olcott:>On 9/5/2024 11:34 AM, joes wrote:It is very well known by this point.Am Thu, 05 Sep 2024 11:10:40 -0500 schrieb olcott:You KEEP TRYING TO CHEAT by erasing the context !!!On 9/5/2024 10:57 AM, joes wrote:>Am Thu, 05 Sep 2024 08:24:20 -0500 schrieb olcott:On 9/5/2024 2:34 AM, Mikko wrote:On 2024-09-03 13:00:50 +0000, olcott said:On 9/3/2024 5:25 AM, Mikko wrote:On 2024-09-02 16:38:03 +0000, olcott said:I don’t know, you claim it’s a decider!How the F--- Does the emulated HHH return?Show the details of how DDD emulated by HHH reaches its own machineBy HHH returning, which we are guaranteed from its definition as a
address 0000217f.
decider.
>DDD emulated by HHH CANNOT POSSIBLY reach its own machine addressOnly HHH can’t simulate it.
0000217f.
>The directly executed HHH correctly determines that its emulated DDDWhy doesn’t the simulated HHH abort?
must be aborted because DDD keeps *THE EMULATED HHH* stuck in recursive
emulation.
>
The first HHH cannot wait for its HHH to abort
which is waiting for its HHH to abort on and on
with no HHH ever aborting.
>
Indeed! There is no way to make HHH correct for all inputs, in particular not for the input that uses HHH's algorithm.
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
Show the details of how DDD emulated by HHH
reaches its own machine address 0000217f.
00002172, 00002173, 00002175, 0000217a calls HHH(DDD)
then
00002172, 00002173, 00002175, 0000217a calls HHH(DDD)...
WHAT SHOULD THE NEXT STEPS BE?
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