Re: Even Google AI Overview understands me now --- different execution traces have different behavior !!!

On 10/6/2024 1:52 PM, Richard Damon wrote:

On 10/6/24 2:32 PM, olcott wrote:

On 10/6/2024 1:13 PM, Richard Damon wrote:

On 10/6/24 2:03 PM, olcott wrote:

On 10/6/2024 12:29 PM, Richard Damon wrote:

On 10/6/24 1:07 PM, olcott wrote:

On 10/6/2024 11:59 AM, Richard Damon wrote:

On 10/6/24 8:39 AM, olcott wrote:

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DDD emulated by each corresponding HHH that can possibly
exist never returns. Each of these HHH emulators that does
return 0 correctly reports the above non-halting behavior.
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No, the DDD return (if the HHH(DDD) gives an answer), just after the HHH that emulated them gave up.
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DDD emulated by each corresponding HHH that can possibly
exist never returns.
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DDD emulated by each corresponding HHH
DDD emulated by each corresponding HHH
DDD emulated by each corresponding HHH
DDD emulated by each corresponding HHH

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Which, as you have been told but seems to be above your head means that the execution of DDD,

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gets to ignore the fact that DDD was defined to
have a pathological relationship with HHH that
HHH cannot ignore.
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No, that isn't ignoring it, but taking into account that since HHH is defined to be a specific program, it has specific behavior.
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The behavior of the executed DDD after the emulated
DDD has already been aborted is different than the
behavior of the emulated DDD that must be aborted.

 Nope, it is the exact same code on the exact same data, and thus does the exact same behavior.
 

The execution trace proves that the executed DDD has
different behavior that need not be aborted because
emulated DDD must be an is aborted.
No one can be stupid enough to think that
NEED NOT BE ABORTED is exactly the same as NEED NOT BE ABORTED
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer