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Am Sat, 12 Oct 2024 17:49:03 -0500 schrieb olcott:https://chatgpt.com/share/6709e046-4794-8011-98b7-27066fb49f3eOn 10/12/2024 5:08 PM, joes wrote:DDD terminates.Am Sat, 12 Oct 2024 14:44:06 -0500 schrieb olcott:That is the same as saying that people are limited in their ability toOn 10/12/2024 2:29 PM, joes wrote:If it's not, all the rest doesn't matter for the halting problem.Am Fri, 11 Oct 2024 17:34:13 -0500 schrieb olcott:I have not even gotten to that point yet.On 10/11/2024 5:20 PM, Richard Damon wrote:>On 10/11/24 6:09 PM, olcott wrote:On 10/11/2024 4:55 PM, Richard Damon wrote:On 10/11/24 5:44 PM, olcott wrote:On 10/11/2024 4:31 PM, Richard Damon wrote:On 10/11/24 5:09 PM, olcott wrote:On 10/11/2024 3:21 PM, Richard Damon wrote:On 10/11/24 1:31 PM, olcott wrote:On 10/11/2024 12:10 PM, Richard Damon wrote:On 10/11/24 11:35 AM, olcott wrote:On 10/11/2024 8:14 AM, Richard Damon wrote:On 10/11/24 8:41 AM, olcott wrote:On 10/11/2024 4:47 AM, Mikko wrote:On 2024-10-11 01:55:37 +0000, olcott said:On 10/9/2024 6:48 PM, Richard Damon wrote:On 10/9/24 2:46 PM, olcott wrote:On 10/9/2024 6:46 AM, Richard Damon wrote:On 10/9/24 7:01 AM, olcott wrote:On 10/9/2024 1:08 AM, Jeff Barnett wrote:On 10/8/2024 6:49 AM, Andy Walker wrote:Whether HHH returns a value seems to be important for determiningThat you can't even pay attention to the fact that we are onlyNo, it shows that HHH can not correctly emulate DDD and return anThere are a pair of C functions having x86 code that specifiesAnd what do you do when I present the output from your ownI already have several expert witnesses that have attested toWhich means for you to claim defamation, you need to prove thatWithin software engineering (C and x86 code, not TuringGO ahead an TRY. The counter-suit would ruin you.The source-code conclusively proves that HHH does correctlyNo, it shows that HHH is first NOT a proper deciderThe source code has always proved that HHH does correctlyThe x86 machine code of DDD and HHH provides the singleRight, and that machine code needs to INCLUDE the machine
correct way to interpret DDD emulated by HHH.
code of HHH,
emulate itself emulating DDD.
emulate itself emulating DDD. No matter how you deny this
your denial of these exact details <is> libelous.
*This is to be taken as an official cease-and-desist order*
And, you would need to persuade some lawyer to take your case
to even start, and I suspect that would be difficult
considering your case.
I suspect that in the first deposition you would just create
obvious contradiction making you guilty of perjury.
Your source code proves that HHH doesn't "Correctly Simulate"
per the standard needed to determine halting, as partial
simulation are no
machines)
HHH does correctly emulate itself emulating DDD according to
the semantics of the x86 language.
No matter how you try to rebut this verified fact you would
meet the negligence requirement of defamation suits.
my statements are actually false.
Since I can show that you statement are incorrect, that can't
be shown.
Your conclusion can NOT come from your premises except by
relying on equivocation, and thus your statement is not
correct, and calling it wrong is not a lie, so can not be
defamitory.
the fact that DDD emulated by the same HHH that it calls cannot
possibly return.
program that shows that DDD returns.
Then present the definition of Halting as being about the machine
itself, and that the definition of the Halting Problem is about
the behavior of the machine defined by the input.
that DDD correctly emulated by HHH cannot possibly return.
answer.
talking about the behavior of DDD emulated by HHH and not talking
about whether or not HHH returns a value would seem to be a good
incompetence defense to defamation.
whether it is, in fact, a decider.
>My point HERE AND NOW is that DDD emulated by every HHH that canYes, it depends on HHH. HHH cannot simulate DDD to its termination.
possibly exist cannot possibly reach its own return instruction NO
MATTER WHAT HHH DOES.
calculate the diameter of a square.
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