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On 10/14/2024 6:50 PM, Richard Damon wrote:Your projection is amazing. IT is YOU that has an EMOTIONAL investment in the problem, because you need for it not to be true to prove you life long idea that just isn't true.On 10/14/24 12:07 PM, olcott wrote:People have such deep emotional investment in the haltingOn 10/14/2024 10:46 AM, joes wrote:>Am Mon, 14 Oct 2024 10:38:00 -0500 schrieb olcott:>On 10/14/2024 6:21 AM, Richard Damon wrote:>On 10/14/24 5:49 AM, olcott wrote:It proves that it has a much deeper understanding than anything that IOn 10/14/2024 4:04 AM, Mikko wrote:No, it admits that DDD does halt, but that HHH must be correct to sayOn 2024-10-13 12:53:12 +0000, olcott said:https://chatgpt.com/share/6709e046-4794-8011-98b7-27066fb49f3e
>Although it is possible for LLM systems to lie:No reasoning shown.
ChatGPT does correctly apply truth preserving operations to the
premises that it was provided regarding the behavior of DDD and HHH.
*Try to find a mistake in its reasoning*
When you click on the link and try to explain how HHH must be wrong
when it reports that DDD does not terminate because DDD does terminate
it will explain your mistake to you.
it doesn't, ... because of the lies you told it.
told it.A program is a C function called from main(). This corresponds to theIts reasoning is based on the incorrect presumption that the HHH that(1) DDD never has been a program it is a C function.
DDD calls is not part of the program DDD,
(2) HHH does correctly emulated itself emulating DDD
this <is> a contiguous sequence of computation.
behaviour of the actual execution.
>
I said that DDD never has never been a program and
you change the subject as your strawman deception rebuttal.
And thus you admit that you have been lying about working on the Halting problem.
>
problem that they will not talk about it rationally through
an accurate proxy.
THE FOLLOWING IS NECESSARILY TRUE YET EVERYONE CONCLUDESNo, you are so invested in your lie that you refuse to see the truth.
THAT IT IS FALSE BECAUSE THEY ALREADY MADE UP THEIR MIND.
void DDD()Again, your equivocation.
{
HHH(DDD);
return;
}
When HHH is an x86 emulation based termination analyzer
then each DDD emulated by any HHH that it calls never returns.
Each of the directly executed HHH emulator/analyzers that returnsWhich just proves you are lying, as it has been proven wrong.
0 correctly reports the above non-terminating behavior of its input.
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