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On 10/17/2024 5:07 AM, joes wrote:But it is also a fact that the HHH that tries to correctly emulate that DDD in a way that shows the final behavior of that input, doesn't ever answer.Am Wed, 16 Oct 2024 15:06:01 -0500 schrieb olcott:On 10/16/2024 3:02 PM, joes wrote:Only because they aren't simulated. But they are still terminatingAm Wed, 16 Oct 2024 14:39:37 -0500 schrieb olcott:They would not all abort when you pay close attention to ALL of theOn 10/16/2024 2:33 PM, joes wrote:Then HHH should report itself as halting, when they would all abort.Am Wed, 16 Oct 2024 13:59:58 -0500 schrieb olcott:In other words you continue to fail to understand that unless theOn 10/16/2024 1:47 PM, joes wrote:Exactly, because your nested HHHs do not abort.Am Wed, 16 Oct 2024 13:35:01 -0500 schrieb olcott:Which totally does not matter to the slightest degree when you haveOn 10/16/2024 1:06 PM, joes wrote:>Am Wed, 16 Oct 2024 12:46:01 -0500 schrieb olcott:On 10/16/2024 12:27 PM, joes wrote:Am Wed, 16 Oct 2024 10:39:21 -0500 schrieb olcott:On 10/16/2024 9:45 AM, joes wrote:Am Wed, 16 Oct 2024 09:11:22 -0500 schrieb olcott:On 10/16/2024 9:01 AM, joes wrote:Am Wed, 16 Oct 2024 08:31:43 -0500 schrieb olcott:On 10/16/2024 1:33 AM, joes wrote:In practice you programmed H impurely.In theory this seems true when ignoring or failing to comprehendAnd if the first one does, all of them do.If the first HHH to meet its abort criteria does not act on thisWhereupon the simulated HHH would abort, if it weren'tHHH is correctly emulating (not simulating) the x86 languageYou are not simulating the given program, but a version thatTHIS IS ALSO THE INDUSTRY STANDARD DEFINITION It isTerminating C functions must reach their "return"Which DDD does.
statement.
stipulated that *correct_x86_emulation* means that a finite
string of x86 instructions is emulated according to the
semantics of the x86 language beginning with the first bytes
of this string.
differs in the abort check.
finite string of DDD including emulating the finite string of
itself emulating the finite string of DDD up until the point
where the emulated emulated DDD would call HHH(DDD) again.
unnecessarily aborted.
criteria then none of them do.
key details.
the discipline to stay within the precisely designated scope of the
exact words that I am saying.
When HHH is an x86 emulation based termination analyzer then each
DDD *correctly_emulated_by* any HHH that it calls cannot possibly
return no matter what this HHH does.
first one aborts then none of them can possibly abort because they all
have the exact same code.
details. It is utterly impossible for any of them besides the outermost
one to abort because it aborts before any of the rest of them see their
abort criteria has been met.programs. An infinite loop is still non-halting even if I never run it.This is just over your head.
>
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
When DDD is correctly emulated by HHH according
to the semantics of the x86 language DDD cannot
possibly reach its own machine address [00002183]
no matter what HHH does.
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